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Bas_tet [7]
3 years ago
8

If √2=1.414,√3=1.find the value of 1/√3+√2.​

Mathematics
1 answer:
Pie3 years ago
3 0

Answer:

0.318

Step-by-step explanation:

\frac{1}{ \sqrt{3} +  \sqrt{2}  }  \\  \\  = \frac{1}{ (\sqrt{3} +  \sqrt{2} ) }  \times  \frac{( \sqrt{3}  -  \sqrt{2}) }{(\sqrt{3}  -  \sqrt{2} )}  \\  \\  = \frac{1 \times ( \sqrt{3}  -  \sqrt{2}) }{(\sqrt{3}) ^{2}   -  (\sqrt{2} )^{2} }  \\  \\  = \frac{ \sqrt{3}  -  \sqrt{2}}{3 - 2}   \\  \\  = \frac{ \sqrt{3}  -  \sqrt{2}}{1}    \\  \\  = \sqrt{3}  -  \sqrt{2} \\  \\  = 1.732 - 1.414 \\  \\    \huge \red{ \boxed{ \frac{1}{ \sqrt{3} +  \sqrt{2}  } = 0.318}}

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