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OverLord2011 [107]
3 years ago
5

Which point has coordinates (4, StartFraction 3 pi Over 4 EndFraction) A B C D

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
8 0

Answer:

B on Edge

Step-by-step explanation:

Edge2020

yan [13]3 years ago
7 0

Answer:

B

Step-by-step explanation:

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Question 4 of 10
stiks02 [169]

Answer:

28° A

Step-by-step explanation:

we have isosceles triangle, which's 2 sides and 2 angles are equal.

we have two equal sides, so another side is base.

base angles are equal, so if E=28 thenG=28 too

3 0
3 years ago
Erik is bisecting a segment with technology. Which of the following describes his next step? Draw a circle with a center C and a
lana [24]

Answer:

Trace a line between the intersection of the two circles.

Step-by-step explanation:

This is a very important technique, the next thing you do is trace a line in between the intersection of the circles and that would intercept your circle. I will show you in a drawing.

7 0
3 years ago
B-2-11. Find the inverse Laplace transform of s + 1/s(s^2 + s +1)
Aleksandr-060686 [28]

Answer:

\mathcal{L}^{-1}\{\frac{s+1}{s(s^{2} + s +1)}\}=1-e^{-t/2}cos(\frac{\sqrt{3} }{2}t )+\frac{e^{-t/2}}{\sqrt{3} }sin(\frac{\sqrt{3} }{2}t)

Step-by-step explanation:

let's start by separating the fraction into two new smaller fractions

.

First,<em> s(s^2+s+1)</em> must be factorized the most, and it is already. Every factor will become the denominator of a new fraction.

\frac{s+1}{s(s^{2} + s +1)}=\frac{A}{s}+\frac{Bs+C}{s^{2}+s+1}

Where <em>A</em>, <em>B</em> and <em>C</em> are unknown constants. The numerator of <em>s</em> is a constant <em>A</em>, because <em>s</em> is linear, the numerator of <em>s^2+s+1</em> is a linear expression <em>Bs+C</em> because <em>s^2+s+1</em> is a quadratic expression.

Multiply both sides by the complete denominator:

[{s(s^{2} + s +1)]\frac{s+1}{s(s^{2} + s +1)}=[\frac{A}{s}+\frac{Bs+C}{s^{2}+s+1}][{s(s^{2} + s +1)]

Simplify, reorganize and compare every coefficient both sides:

s+1=A(s^2 + s +1)+(Bs+C)(s)\\\\s+1=As^{2}+As+A+Bs^{2}+Cs\\\\0s^{2}+1s^{1}+1s^{0}=(A+B)s^{2}+(A+C)s^{1}+As^{0}\\\\0=A+B\\1=A+C\\1=A

Solving the system, we find <em>A=1</em>, <em>B=-1</em>, <em>C=0</em>. Now:

\frac{s+1}{s(s^{2} + s +1)}=\frac{1}{s}+\frac{-1s+0}{s^{2}+s+1}=\frac{1}{s}-\frac{s}{s^{2}+s+1}

Then, we can solve the inverse Laplace transform with simplified expressions:

\mathcal{L}^{-1}\{\frac{s+1}{s(s^{2} + s +1)}\}=\mathcal{L}^{-1}\{\frac{1}{s}-\frac{s}{s^{2}+s+1}\}=\mathcal{L}^{-1}\{\frac{1}{s}\}-\mathcal{L}^{-1}\{\frac{s}{s^{2}+s+1}\}

The first inverse Laplace transform has the formula:

\mathcal{L}^{-1}\{\frac{A}{s}\}=A\\ \\\mathcal{L}^{-1}\{\frac{1}{s}\}=1\\

For:

\mathcal{L}^{-1}\{-\frac{s}{s^{2}+s+1}\}

We have the formulas:

\mathcal{L}^{-1}\{\frac{s-a}{(s-a)^{2}+b^{2}}\}=e^{at}cos(bt)\\\\\mathcal{L}^{-1}\{\frac{b}{(s-a)^{2}+b^{2}}\}=e^{at}sin(bt)

We have to factorize the denominator:

-\frac{s}{s^{2}+s+1}=-\frac{s+1/2-1/2}{(s+1/2)^{2}+3/4}=-\frac{s+1/2}{(s+1/2)^{2}+3/4}+\frac{1/2}{(s+1/2)^{2}+3/4}

It means that:

\mathcal{L}^{-1}\{-\frac{s}{s^{2}+s+1}\}=\mathcal{L}^{-1}\{-\frac{s+1/2}{(s+1/2)^{2}+3/4}+\frac{1/2}{(s+1/2)^{2}+3/4}\}

\mathcal{L}^{-1}\{-\frac{s+1/2}{(s+1/2)^{2}+3/4}\}+\mathcal{L}^{-1}\{\frac{1/2}{(s+1/2)^{2}+3/4}\}\\\\\mathcal{L}^{-1}\{-\frac{s+1/2}{(s+1/2)^{2}+3/4}\}+\frac{1}{2} \mathcal{L}^{-1}\{\frac{1}{(s+1/2)^{2}+3/4}\}

So <em>a=-1/2</em> and <em>b=(√3)/2</em>. Then:

\mathcal{L}^{-1}\{-\frac{s+1/2}{(s+1/2)^{2}+3/4}\}=e^{-\frac{t}{2}}[cos\frac{\sqrt{3}t }{2}]\\\\\\\frac{1}{2}[\frac{2}{\sqrt{3} } ]\mathcal{L}^{-1}\{\frac{\sqrt{3}/2 }{(s+1/2)^{2}+3/4}\}=\frac{1}{\sqrt{3} } e^{-\frac{t}{2}}[sin\frac{\sqrt{3}t }{2}]

Finally:

\mathcal{L}^{-1}\{\frac{s+1}{s(s^{2} + s +1)}\}=1-e^{-t/2}cos(\frac{\sqrt{3} }{2}t )+\frac{e^{-t/2}}{\sqrt{3} }sin(\frac{\sqrt{3} }{2}t)

7 0
4 years ago
What is the value of the expression
pishuonlain [190]

Answer:

Step-by-step explanation:

Give more

8 0
3 years ago
PLZ HELP ASAP SOLVE SIMMILAR TRIANGLES
Shkiper50 [21]
For this case by similarity of triangles we can use the following relationship:
 (x) / (11) = (2) / (10)
 We clear the value of x:
 x = ((2) / (10)) * (11)
 Rewriting:
 x = ((1) / (5)) * (11)
 x = 2.2
 Equivalently:
 x = 22/10
 x = 11/5
 Answer:
 
The value of x is:
 
x = 2.2
 
Equivalently:
 
x = 11/5
6 0
4 years ago
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