The probibility of Alonzo pulling out two green marbles is 2/9 I believe.
I hope this helps
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be

.
You're minimizing

subject to the constraint

. Note that

and

attain their extrema at the same values of

, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.
The Lagrangian is

Take your partial derivatives and set them equal to 0:

Adding the first three equations together yields

and plugging this into the first three equations, you find a critical point at

.
The squared distance is then

, which means the shortest distance must be

.
For this case we must resolve the following inequality:

Adding 7 to both sides of the inequality:

Different signs are subtracted and the major sign is placed.

Thus, the solution is given by all the values of "x" less than -5.
The solution set is: (-∞, - 5)
Answer:

See attached image
Answer:
see explanation
Step-by-step explanation:
Using the identity
tan²x = sec²x - 1
Consider left side
sec²x + tan²x
= sec²x + sec²x - 1
= 2sec²x - 1
= right side , thus verified