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nirvana33 [79]
3 years ago
13

Graph the image of the given triangle, reflected across the y-axis. Select the Polygon tool. Then, click the points of the trian

gle vertices to create the triangle by connecting the sides Polygon * Move Undo Redo x Reset y 10 9 8 7 6 5 4 3 2 1 2 3 10-9 -9 -7 -6 -5 -4 -3 -2 -10 1 4 5 6 7 8 9 10​

Mathematics
1 answer:
Triss [41]3 years ago
7 0

Hi! I just took the test and the photo below is the correct answer. Hope this helps and have a great day :)

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Rewrite 2(x + 3y - 2z) using the Destributive Property
zloy xaker [14]

Answer:

2x+6y-4z

Step-by-step explanation:

multiply the two by each term and coefficient inside of the parentheses

6 0
2 years ago
Y=2x+1 when x increases by 5,y increases by​
Dmitriy789 [7]

Answer:

10

Step-by-step explanation:

say x=0

then y would be 1

increasing x by 5 makes x=5

and then 5 x 2 + 1=11

so y went from 1-11(difference of 10) with the variation

so the answer is 10

3 0
1 year ago
Jen had 60 fossils. If she put 6 fossils in each box, how many boxes were there?
Monica [59]

Answer:

10 boxes

Step-by-step explanation:

Take the number of fossils and divide by the number per box to determine the number of boxes

60/6 = 10

She needs 10 boxes

5 0
3 years ago
Read 2 more answers
Subtract. Write the answer in standard form. (12+4i)−(3−7i)
LiRa [457]

Answer:

9+11i

Step-by-step explanation:

12-3=9

4i-(-7i)=11

8 0
2 years ago
Read 2 more answers
A company with n employees publishes an internal calendar, where each day lists the employees having a birthday that day. What i
lutik1710 [3]

Answer: 1-(\frac{364}{365})^n

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^x, where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.

We assume that the total number of days in a particular year are 365.

Then , the probability for each employee to have birthday on a certain day :

p=\dfrac{1}{365}

Given : The number of employee in the company = n

Then, the probability there is at least one day in a year when nobody has a birthday is given by :-

P(x\geq1)=1-P(x

Hence, the probability there is at least one day in a year when nobody has a birthday =1-(\frac{364}{365})^n

5 0
3 years ago
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