Step 1: Find f'(x):
f'(x) = -6x^2 + 6x
Step 2: Evaluate f'(2) to find the slope of the tangent line at x=2:
f'(2) = -6(2)^2 + 6(2) = -24 + 12 = -12
Step 3: Find f(2), so you have a point on y=f(x):
f(2) = -2·(2)^3 + 3·(2)^2 = -16 + 12 = -4
So, you have the point (2,-4) and the slope of -12.
Step 4: Find the equation of your tangent line:
Using point-slope form you'd have: y + 4 = -12 (x - 2)
That is the equation of the tangent line.
If your teacher is picky and wants slope-intercept, solve that for y to get:
y = -12 x + 20
Answer:
4
x
−
1
3
y
=
−
2
To convert this equation to slope-intercept form, solve for
y
.
Subtract
4
x
from both sides.
−
1
3
y
=
−
2
−
4
x
Simplify
−
1
3
y
to
−
y
3
−
y
3
=
−
2
−
4
x
Multiply both sides times
3
.
−
y
=
−
2
(
3
)
−
4
x
(
3
)
Simplify.
−
y
=
−
6
−
12
x
Rearrange the right side.
−
y
=
−
12
x
−
6
Multiply both sides times
−
1
.
y
=
12
x
+
6
m
=
12
and
b
=
6
.
Step-by-step explanation:
Answer: 5
This is because (4r + 6) means you take r and multiply that number by 4.
Because there is no number, r would equal one in this case.
4 • 1 is 4
4 + 6 is 10
This would give us 1/2(10)
Half of 10 is 5.
Therefore, the answer is 5.
Answer: a and c
Step-by-step explanation:
I know it’s not b but isn’t adjacent angel two angels?
Correct me if I’m wrong
