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3 years ago

What is 3d + 8 = 2d - 17 its a equation

Mathematics

2 answers:

maksim [4K]3 years ago

8 0

3d+8=2d-17
-2d -2d
__________
d+8=-17
-8 -8
__________
d=-25

Arlecino [84]3 years ago

6 0

3d + 8 = 2d - 17

Subtract 8 from both sides.

3d = 2d - 17 - 8

Subtract 2d from both sides.

3d - 2d = -17 - 8

Simplify.

d = -25

~Hope I helped!~

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Please help guys this question is from geometry I really need your help

IrinaK [193]

Answer:

$\bold{\boxed{Check explaination for better understanding!}}$

z=65,y=65,x=50

Step-by-step explanation:

Firstly, let's identify the only angle provided. The angle is an exterior angle.

The exterior angle theorm states that greater than either of the measures of the remote interior angles.

Let's remember that and start solving!

The exterior angle and x form a supplimentary line which means they create 180 degrees.

130+x=180

x=50

Now by the theorm the sum of z+y should be equal to the exterior angle which is 130.

Simply, z+y=130.

So z is equal to 65, and y is equal to 65.

Let's check our answers now.

z=65,y=65,x=50

z+x+y=180

65+50+65=180! That works :)

Hope it helps! :))

8 0

3 years ago

Find the area of the region bounded by the graphs of y = x, y = −x + 4, and y = 0.

Marrrta [24]

The line y = x and y = -x + 4 intersect when at the point (2, 2).

Expresing y = -x + 4 in terms of x, we have x = 4 - y.

Thus, the area of the region bounded by the graphs of y = x, y = −x + 4, and y = 0 is given by

$\int\limits^2_0 {(y-(4-y))} \, dy = \int\limits^2_0 {(y-4+y)} \, dy \\ \\ = \int\limits^2_0 {(2y-4)} \, dy= \left[y^2-4y\right]_0^2 =|(2)^2-4(2)| \\ \\ =|4-8|=|-4|=4$

Therefore, the area bounded by the lines is 4 square units.

4 0

3 years ago

Can somebody help me with this?

Natasha_Volkova [10]

Step-by-step explanation:

Hey there!

By looking through figure, l and m are parallel lines and a transversal line passes through the lines.

Now,

7x + 12° = 12x - 28°( alternate angles are equal)

12°+28° = 12x - 7x

40° = 5x

$x = \frac{40}{5}$

Therefore, x = 8°

Now,

12x - 28° + 9y - 77 = 180° ( being linear pair)

12×8° - 28° + 9y -77° = 180°

96° - 28° + 9y - 77° = 180°

-9 + 9y = 180°

9y = 180° + 9°

y = 189°/9

Therefore, y = 21°

Therefore, X = 8° and y= 21° .

Hope it helps....

4 0

4 years ago

Solve the system: x + 5y = -15 -2x -10y = 30*

Ksju [112]

Answer:

x= -5/3 y-5

Step-by-step explanation:

6 0

3 years ago

A neighborhood was given a vacant lot in the shape of a rectangle on which to build a park. The neighborhood is considering how

Montano1993 [528]

Answer:

The triangle and trapezoid area formulas have One-half in them.

In the trapezoid formula, the bases are added.

Step-by-step explanation:

Topic: Plane Shapes

Basically, the requirement of the question is to compare area of shapes. The shapes are

Trapezoid
Triangle
Parallelogram
Rectangle

The Area of a Trapezoid is $(\frac{a + b}{2} )h$ where a and b are the bases of the trapezoid and h is the height

The Area of a Triangle is $\frac{bh}{2}$ where b and h are the base and the height of the triangle respectively

The Area of a Parallelogram is $b * h$ where b and h are the bases and the height of the parallelogram

The Area of a Rectangle is $l * b$ where l and b are the length and the breadth of the triangle respectively

Checking option a through e

A. The triangle and trapezoid area formulas have One-half in them.

True; Area of a Triangle is $\frac{bh}{2}$ while Area of a Trapezoid is $(\frac{a + b}{2} )h$

B. The parallelogram and rectangle formulas are both the same.

False; Area of a Parallelogram is $b * h$ while Area of a Rectangle is $l * b$

C. In the parallelogram formula, the bases are added.

False; The basis are not added

Area of a Parallelogram is $b * h$

D. In the trapezoid formula, the bases are added.

True; Area of a Trapezoid is $(\frac{a + b}{2} )h$

E. In the triangle formula, the sides are added, then multiplied by One-half.

False; Area of a Triangle is $\frac{bh}{2}$

4 0

4 years ago

Read 2 more answers