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faltersainse [42]
3 years ago
10

Math work plz, i just need to get an answer

Mathematics
2 answers:
Allushta [10]3 years ago
8 0
5x + 5y = 15
x = -y + 3

2x - 2y = 10
2(-y + 3) - 2y = 10
-2y + 6 -2y = 10
-4y = 4
y = -1

5x + 5y = 15
5x + 5(-1) = 15
5x -5 = 15
x = 4

the answer is (4,-1)
Neporo4naja [7]3 years ago
6 0
It is 10, and 15 I believe
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\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

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We have a point of estimate for the sample mean with this formula:

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And for the margin of error we have the following estimation:

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

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see attachment

x\in\langle-4,4\rangle

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