-(4-x)=3/4(x-6) please help me please i require assistance please and thank you

What number goes in the missing space? 5,2,10 3,3,9 2,6,?

vfiekz [6]

You can notice the sequence:
5*2=10
3*3=9
following the same sequence:
2*6=12
therefore, the missing number is 12
(2,6,12)

8 0

4 years ago

Read 2 more answers

1

antoniya [11.8K]

Answer:

4/5

Step-by-step explanation:

1, 2 , 3 and 4 are factors of 12

so 4 out of 5

4/5 is the probability of getting factor of 12

3 0

3 years ago

What will be the value of

madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

$\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}$

Then you want to know the value of

$\displaystyle\lim_{n\to\infty}a_n$

if it exists.

To show the limit exists and that $a_n$ converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that $a_1=\sqrt{42}\le\sqrt{49}=7$ . Suppose $a_k\le 7$ . Then $a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7$ . So by induction, $a_n$ is bounded above by 7 for all $n$ .

Monontonicity: We have $a_1=\sqrt{42}$ and $a_2=\sqrt{42+\sqrt{42}}$ . It should be quite clear that $a_2>a_1$ . Suppose $a_k>a_{k-1}$ . Then $a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k$ . So by induction, $a_n$ is monotonically increasing.