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agasfer [191]
3 years ago
9

A car drives 494 km in 4 hours 45 minutes what is its average speed in kilometers per hour?

Mathematics
1 answer:
Artist 52 [7]3 years ago
6 0

The average speed is 104 kilometer per hour

<em><u>Solution:</u></em>

Given that,

A car drives 494 km in 4 hours 45 minutes

To find: Average speed in kilometers per hour

<em><u>The average speed is given by formula:</u></em>

Average\ speed = \frac{distance}{time}

From given,

Distance = 494 km

Time = 4 hours 45 minutes

We know that,

1 hour = 60 minutes

Therefore,

45\ minutes = \frac{45}{60}\ hour\\\\45\ minutes = 0.75\ hour

Thus,

time = 4 hours 45 minutes = 4 hour + 0.75 hour = 4.75 hour

<em><u>Thus average speed is:</u></em>

Average\ speed = \frac{494}{4.75}\\\\Average\ speed = 104

Thus average speed is 104 kilometer per hour

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You must design a closed rectangular box of width w, length l and height h, whose volume is 504 cm3. The sides of the box cost 3
Charra [1.4K]

Answer:

Dimensions will be

Length = 7.23 cm

Width = 7.23 cm

Height = 9.64 cm

Step-by-step explanation:

A closed box has length = l cm

width of the box = w cm

height of the box = h cm

Volume of the rectangular box = lwh

504 = lwh

h=\frac{504}{lw}

Sides which involve length and width and height, cost = 3 cents per cm²

Top and bottom of the box costs = 4 cents per cm²

Cost of the sides C_{s}= 3[2(l + w)h] = 6(l + w)h

C_{s}= 3[2(l + w)h]

C_{s}=6(l+w)(\frac{504}{lw} )

Cost of the top and the bottom C_{(t,p)}= 4(2lw) = 8lw

Total cost of the box C = 3024\frac{(l+w)}{lw} + 8lw

                                      = 3024[\frac{1}{l}+\frac{1}{w}] + 8lw

To minimize the cost of the sides

\frac{dC}{dl}=3024(-l^{-2}+0)+8w=0

\frac{3024}{l^{2}}=8w

\frac{378}{l^{2}}=w ---------(1)

\frac{dC}{dw}=3024(-w^{-2})+8l=0

\frac{3024}{w^{2}}=8l

\frac{378}{w^{2}}=l

w^{2}=\frac{378}{l}-------(2)

Now place the value of w from equation (1) to equation (2)

(\frac{378}{l^{2}})^{2}=\frac{378}{l}

\frac{(378)^{2} }{l^{4}}=\frac{378}{l}

l³ = 378

l = ∛378 = 7.23 cm

From equation (2)

w^{2}=\frac{378}{7.23}

w^{2}=52.28

w = 7.23 cm

As lwh = 504 cm³

(7.23)²h = 504

h=\frac{504}{(7.23)^{2}}

h = 9.64 cm                        

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3 years ago
The angle of depression from the basketball hoop to Claire’s eyes is 9.2°. The vertical distance from the ground to Claire’s eye
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3 years ago
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Alekssandra [29.7K]

Answer:

A

Answer is A.

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3 years ago
Number 6 part a &amp; b<br> Number 7<br> Please &amp; thank you
miv72 [106K]

Answer:

6- Part A: 750a+1200r=1000000

    Part B: 1065a+876r=1000000

Solution of the system: a\approx521.739\;\;\;\;b\approx507.246

Step-by-step explanation:

<u>Part A:</u>

In words, the equation is formed like this:

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Now, the total of each yield is calculated by the product of kg/hectare and number of hectares. Thus, the equation is:

750a+1200r=1000000

<u>Part B:</u>

In words:

Arabica's worth + Robusta's worth  = plantation worth

Each yield's worth is given by the product of the price per kg and the corresponding production. So, the equation is:

1.42(750a)+0.73(1200r)=1000000\\1065a+876r=1000000

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3 years ago
Kenji buys 3 yards of fabric for 7.47.Then he realizes that he needs 2 more yards.How much will the extra fabric cost
AleksAgata [21]

7.47/3 = 2.49

1 yard = 2.49

2 x 2.49 =

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