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postnew [5]
2 years ago
9

The data represents the height, in feet, of various buildings. Find the Interquartile Range.

Mathematics
1 answer:
N76 [4]2 years ago
7 0

Answer: 6

Step-by-step explanation:

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Factor the expression and simplify as much as possible. 24x(x2 1)4(x3 1)5 42x2(x2 1)5(x3 1)4
zmey [24]

Answer: 120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

Step-by-step explanation:

=24x(x^2 + 1)4(x^3 + 1)5 + 42x^2(x^2 + 1)5(x^3 + 1)4

Remove the brackets first

=[(24x^3 +24x)(4x^3 + 4)]5 + [(42x^4 +42x^2)(5x^3 + 5)4]

=[(96x^6 + 96x^3 +96x^4 + 96x)5] + [(210x^7 + 210x^4 + 210x^5 + 210x^2)4]

=(480x^6 + 480x^3 + 480x^4 + 480x) + (840x^7 + 840x^4 + 840x^5 + 840x^2)

Then the common:

=[480(x^6 + x^3 + x^4 + x) + 840(x^7 + x^4 + x^5 + x^2)]

=120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

6 0
3 years ago
Multiply (2x+1)(6x^2+8+9)
spayn [35]

Answer:

12x3+6x2+34x+17

Step-by-step explanation:

(2x+1)(6x2+8+9)

=(2x+1)(6x2+8+9)

=(2x)(6x2)+(2x)(8)+(2x)(9)+(1)(6x2)+(1)(8)+(1)(9)

=12x3+16x+18x+6x2+8+9

=12x3+6x2+34x+17

6 0
2 years ago
Expand and simplify 2(5x - 1) – (2x - 5) ​
horrorfan [7]

Answer:

2(5x - 1) – (2x - 5)

=2(5x−1)−2x+5

=10x−2−2x+5

=(10x−2x)+(−2+5)

=8x+3

Step-by-step explanation:

3 0
2 years ago
What is the base if the height is 6ft and the area is 14 ft on a triangle ​
insens350 [35]

Answer:

b = 4.66666667

Step-by-step explanation:

The equation for finding the area of a triangle is

0.5b x h = a

b = base

h = height

a = area

So I calculated 14 divided by 6

And got 2.3333333

And since that number is half of the base, I multiplied it by 2

2.333 x 2 ≈ 4.66666667

4 0
3 years ago
Explain why their are no solutions to the system of inequalities <br> y ≤2x-5 <br> y ≥2x+1
rosijanka [135]

Answer:

Sorry this is late and I think this is right.

They are both parallel, they have the same slope, and do <em>not </em>intersect. If you were to draw a slope out for it, you would find this to be true.

For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:

<em>y < - 1/2x -3</em>

<em>y > 1/2x + 2</em>

<em>y= -x/2 -3</em> and <em>y= -x/2 + 2 </em>have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.

I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.

7 0
3 years ago
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