Answer:
3040000mm³
Step-by-step explanation:
Volume of a cube = a³ ; a = size of edge
Volume of cubical tank = 12³ = 12 * 12 * 12 = 1728 cm³
Half filled cube = 1728 / 2 = 864 cm³
Volume is f rectangular tank :
V = length * width * height
V = 10 * 8 * 7 = 560 cm³
Volume of water left in cubical tank :
(864 - 560) = 304cm³
1cm³ = 1000mm³
304cm³ = 304 * 1000 = 3040000mm³
Hello
the line passes by A ( 0 ; -2) and B (5 ; 0) equation : y = ax+b
a is a slop : a = (yb - ya)/(xb -xa)
a = (0+2)/(5-0)
a =2/5
y = (2/5)x+b
if x=5 and y= 0
0 = (2/5)(5)+b
b= - 2
the equation is : y = (2/5)x-2
Answer:
d
Step-by-step explanation:
Answer:
Cos A=5/13
we have
Cos² A=
25/169=1-Sin²A
sin²A=1-25/169
sin²A=144/169
Sin A=
again
Tan B=4/3
P/b=4/3
p=4
b=3
h=
Now
Sin B=p/h=4/5
in IV quadrant sin angle is negative so
Sin B=-4/5
CosB=b/h=3/5
Now
<u>S</u><u>i</u><u>n</u><u>(</u><u>A</u><u>+</u><u>B</u><u>)</u><u>:</u><u>s</u><u>i</u><u>n</u><u>A</u><u>c</u><u>o</u><u>s</u><u>B</u><u>+</u><u>C</u><u>o</u><u>s</u><u>A</u><u>s</u><u>i</u><u>n</u><u>B</u>
<u>n</u><u>o</u><u>w</u><u> </u>
<u>substitute</u><u> </u><u>value</u>
<u>Sin(A+B):</u>12/13*3/5+5/13*(-4/5)=36/65-4/13
<u>=</u><u>1</u><u>6</u><u>/</u><u>6</u><u>5</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u>
Answer:
10m/s
Step-by-step explanation:
The answer should be 10m/s. Hope it helps!