Answer:
y = 2 ( x − 1 ) ^ 2 + 2
Step-by-step explanation:
y = a ( x − h ) ^ 2 + k
where vertex is (h,k) = (1,2)
h=1, k=2
y = a ( x − 1 ) ^ 2 + 2
sub ( 3,10)
10 = a (3 - 1)^2 + 2
a=2
y = 2 ( x − 1 ) ^ 2 + 2
Answer:
f(x) = 3 cos (2Pi / period value ; x )+ 2
or see answer using 2 as the period see answer in bold below.
Step-by-step explanation:
cosine function amplitude of 3 is A = 3
The period is used to find B
You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle
C is the adding value.
Acos (Bx) + C
A = 3
Bx = 2 pi / period
C = + 2
However f 2 is also the period found
then we just plug in 2 to above formula
f(x) = 3 cos (2Pi / 2 ; x )+ 2
f(x) = 3cos (x pi) + 2
The box has 450 bars in it. 18 times 25 would equal 450
x(t) = 20t
y(t) = 40t - 5t^2
Since we are only interested in comparing the two at time t = 5 seconds, we plug in 5 everywhere we see the variable t and then compare x and y
x(5) = 20(5) becomes x(5) = 100
y(5) = 40(5) - 5(5)^2 becomes y(5) = 200 - 125 and then y(5) = 75
The ratio of y to x can be expressed as: y/x, so we can say the ratio is equal to 75/100 or 0.75
Answer: 0.75
Answer:
C
Step-by-step explanation:
transposition
3x/4=1/5
xc=yc
15x/20×20=4/20×20
15x=4
x=4/15
