Answer:
The margin of error for a 95% confidence interval estimate for the population mean using the Student's t-distribution is of 6.22 ounces.
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 23 - 1 = 22
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 22 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0739
The margin of error is:
M = T*s
In which s is the standard deviation of the sample.
In this question:
s = 3.
Then
M = 2.0739*3 = 6.22
The margin of error for a 95% confidence interval estimate for the population mean using the Student's t-distribution is of 6.22 ounces.
P=2l+2w
P=2(120)+2(90)
P=240+180
P=420
420 feet of fencing is needed.
Answer:
b = -4
Step-by-step explanation:
![\frac{b}{4} + 2 = 1\\\\\frac{b}{4} = -1\\\\b = -4](https://tex.z-dn.net/?f=%5Cfrac%7Bb%7D%7B4%7D%20%2B%202%20%3D%201%5C%5C%5C%5C%5Cfrac%7Bb%7D%7B4%7D%20%3D%20-1%5C%5C%5C%5Cb%20%3D%20-4)
Using division, the 8 cupcakes are there in 28 ounce package if one cupcake weighs 3 1/2.
According to the question,
One cupcake weighs 3 1/2 ounces. In order to find the number of cupcakes are there in 28 ounce package.
1 cupcake = 7/2 ounces
x cupcakes = 28 ounces
28 = 7/2 * x [cross multiplication]
x = (28*2)/7 [Using division]
x = 8
Hence, using division, the 8 cupcakes are there in 28 ounce package if one cupcake weighs 3 1/2.
Learn more about division here
brainly.com/question/18369058
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