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Vlad [161]
3 years ago
8

A large purple bowl contains 5 blue marbles and 3 pink marbles. What is the probability a blue marble is drawn, replaced, and a

second blue marble is drawn?
Mathematics
1 answer:
Blizzard [7]3 years ago
3 0

Answer:

\frac{25}{64}

Step-by-step explanation:

Blue Marbles =5

Pink Marbles =3

Total =3+5=8

Probability of drawing two marbles with replacement

=P(First Blue Marble AND Second Blue Marble)

=P(First Blue Marble) X P(Second Blue Marble)

=\frac{5}{8}X \frac{5}{8}\\\\=\frac{25}{64}

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Answer:


\frac{64}{49}


Step-by-step explanation:


As we can see the given expression as three complex parts and all are being multiplied.


Lets simplify each part separately and then multiply all of them in the end


Part1


(\frac{8.4.2}{8.7})^{2}  

Cancelling 8 in numerator with 8 in denominator


(\frac{4.2}{7})^{2}


(\frac{8}{7})^{2}


\frac{64}{49}


Part2


(\frac{8^{0} }{7^{-3} })^{3}


simpliying


(\frac{1}{7^{-3} })^{3}


({7^{3} })^{3}


7^{9}


Part3


Third part is 7^{-9}, and it does not need to be further simplified


Now multiplying all the three parts


\frac{64}{49}.7^{9}.7^{-9}


\frac{64}{49}.7^{9-9}


\frac{64}{49}.7^{0}


\frac{64}{49}.1


\frac{64}{49}


So our final answer is \frac{64}{49}



5 0
3 years ago
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