Ask question

Ask question

All categories

3 years ago

6

out of 32 students in a class 5 say they will ride there bike to school. Based on the results how many students rode there bike

to school out of 800

2 answers:

yaroslaw [1]3 years ago

8 0

Atleast it is a guess around 100 to 150 hope this helps

Yuki888 [10]3 years ago

7 0

125
divide 5/35 to get .15625 (percent of students who rode bikes would be 15.625%) then multiply the decimal by 800

You might be interested in

1. A cockroach covers a distance of 30 m in

OleMash [197]

Answer:

have you given the solution with questions or not

4 0

3 years ago

Read 2 more answers

Identify the rate of change and term 0<br>1. 3, 5, 7, 9, 11, 13, 15....

yan [13]

Answer:

-1

mark me brainliest

8 0

3 years ago

Solve this dude<br> √10² x (6^3) = ?

gtnhenbr [62]

The answer is 2160. Do you need the steps ?

6 0

3 years ago

Answer question and show work please

SCORPION-xisa [38]

The recipes include: $\frac{1}{2}$ $\frac{3}{8}$ $\frac{3}{10}$
finding their lcm gives:
$\frac{12,20,15}{40}$
arranging them
$\frac{3}{10}$ $\frac{3}{8}$ $\frac{1}{2}$
please mark as brainliest

5 0

3 years ago

1- find the first term= ?, 90, 540, 3240

Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0

3 years ago