Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes

Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.

Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10

A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B

B/A = 102400 / 6400 = 16

There are 16 times as many in B than in A. <<<< Answer

7 0

3 years ago

I need the correct answer please

nikdorinn [45]

So first step is to simplify everything outside of the radicals.
6*2=12
:. The expression is
__ __
12*\| 8 * \| 2
Now we know that
__ __ __
\| 8 = \| 4 * \| 2

And
__ __
\| 2 * \| 2 = 2

And
__
\| 4 = 2

So if we incorporate what we know into the equation, we can figure it out.
So let's first expand the radical 8.
__ __ __
12*\| 4 * \| 2 * \| 2

Now by simplifying the radical four and combining the radical twos, we can get all whole numbers.
12*2*2
Which equals 48.
Answer:48

4 0

3 years ago

I neeed help plz 30 points

Mice21 [21]

Answer:

Step-by-step explanation:

NA = √[(- 4 - 1 )² + (- 3 - 2)²] = 5√2

AT = √[(8 - 1 )² + (1 - 2)²] = 5√2

TS = √[(3 - 8 )² + (- 4 - 1)²] = 5√2

NS = √[(- 4 - 3 )² + (- 3 + 4)²] = 5√2

NA = AT = TS = NS = 5√2

$m_{NA}$ = (- 3 - 2) / (- 4 - 1) = 1 ........ (1)