F = force applied to stop the car = - 3000 N
m = mass of the car = 3000 kg
a = acceleration of the car = ?
v₀ = initial velocity of the car before the force is applied to stop it = 10 m/s
v = final velocity of the car when it comes to stop = 0 m/s
d = stopping distance of the car
acceleration of the car is given as
a = F/m
inserting the values
a = - 3000/3000
a = - 1 m/s²
using the kinematics equation
v² = v²₀ + 2 a d
inserting the values
0² = 10² + 2 (-1) d
0 = 100 - 2 d
2 d = 100
d = 100/2
d = 50 m
hence the correct choice is
C. 50 m
Answer:
that best describes the process is C
Explanation:
This problem is a calorimeter process where the heat given off by one body is equal to the heat absorbed by the other.
Heat absorbed by the smallest container
Q_c = m ce (
-T₀)
Heat released by the largest container is
Q_a = M ce (T_{i}-T_{f})
how
Q_c = Q_a
m (T_{f}-T₀) = M (T_{i} - T_{f})
Therefore, we see that the smaller container has less thermal energy and when placed in contact with the larger one, it absorbs part of the heat from it until the thermal energy of the two containers is the same.
Of the final statements, the one that best describes the process is C
since it talks about the thermal energy and the heat that is transferred in the process
Speaking bout mass,
it's mass is still 40Kg on the moon
but it's Weight on the moon is 1/6mg
Answer:
speed is 81.03 mph
direction is N 3.58 W
Explanation:
given data
travel north = 70 mph
Stream current = 12 mph
direction = S 25° E
result due north = 70 mph
to find out
speed and direction
solution
we will get component of resultant that is
v cosθ and v sinθ
so
( 12cos295 , 12 sin295 ) at ( 0, 70)
as that we can say
v sinθ + 12sin295 = 70 ....................1
v cosθ + 12 cos295 = 0 ......................2
so
vcosθ = -5.0714
vsinθ = 80.8756
now by ratio
cosθ /sinθ = -5.0714/ 80.8756
cot θ = -0.0627
θ = 93.58
so direction is N 3.58 W
and
we know
vcosθ = - 12cos295
v = - 12cos295 / cos(93.58)
v = 81.03 mph
so speed is 81.03 mph
Its acceleration is constant.
