When a ball increases in speed by the same amount each second its acceleration?

two children sit on a merry go round. on sits 0.5 m from the center and the other sits 3 m from the center. Which child has grea

GuDViN [60]

i would say that the child with more linear speed is the cild that is 3 meters away from the center of the merry go round. because the child that is 0.5 meters from the center of the merry go round is less linear because the steering of the merry go round is started from the outer part of the merry go round so it would make more sense that the child that is 3 meters from the center of the merry go round would be more linear in speed.

hope this helps!

8 0

3 years ago

A rocket is launched straight up from the earth's surface at a speed of 1.60×104 m/s . what is its speed when it is very far awa

AlladinOne [14]

16,000 m/s
Since it’s speed, and the distance is unknown. Gravity isn’t applying a noticeable force too on the rocket, as if it were, then the rocket would be accelerating negatively.

7 0

3 years ago

Generally, weather patterns in the U.S. move _____.

blagie [28]

West to east.

The earth is spinning on its own axis. Thus, the area of the equator directly hit by the sun's heat and more solar radiation compared to any other area. That same heat warmth the atmosphere. Warm air rises towards the pole which is cooler. This is the reason of constant movement of the atmosphere.

The Coriolis force governed the air flows towards the pole. While the earth is spinning plus the movement of air north or south, the air follows a <span>curved path, toward the east.</span>

5 0

3 years ago

Read 2 more answers

On a safety test course, a 1000 kg car heading north at 5 m/s collides head-on with an 800 kg car heading south at 4 m/s. At the

Luden [163]

Answer:

The speed is $3.5\frac{m}{s}$ and the direction is heading north.

Explanation:

In collisions the force exerted by the objects that collide is higher enough than the external forces that we can neglect that external forces, with that assumption we can use the conservation fo momentum law that states, final total momentum (pf) is equal initial total momentum (pi) if there’re not external forces or they are small enough to be neglected. Mathematically:

$p_f=p_i$

The total momentum is the sum of the momentum of each of the bodies we're dealing, in our case the moment of each car, then:

$p_{nf}+p_{sf}=p_{ni}+p_{si}$

with pn the momentum of the 1000kg car heading north and ps the 800kg car heading south. Momentum is defined as mass times velocity, then:

$m_nv_{nf}+m_sv_{sf}=m_nv_{ni}+m_sv_{si}$ (1)

It's important to note that when we talk about momentum and velocity direction matters, so we're are going to choose a system of reference where quantities pointing north are positive and pointing south are negative. So, the initial velocity of 1000 kg car is vni=5 m/s, initial velocity of 800 kg car is vsi=-4 m/s and the final velocity of 1000 kg car is vnf=-1 m/s. Now we can solve (1) for vsf and use the values we already have:

$v_{sf}=\frac{m_nv_{ni}+m_sv_{si}-m_nv_{nf}}{m_s}=\frac{(1000)(5)+(800)(-4)-(1000)(-1)}{800}$