Answer:
3.38m
Explanation:
Given parameters:
Time = 4s
Acceleration = 1.3m/s²
Unknown:
Magnitude of the displacement = ?
Solution:
The body starts at rest and the initial velocity is 0m/s. To solve this problem, we have to use the expression below;
S = Ut +
at²
S = displacement
t is the time
a is the acceleration
U is the initial velocity
V is the final velocity
Insert the parameters and solve;
S = (0 x 4) +
x 1.3² x 4 = 3.38m
Answer:The 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.
As we move away from the nucleus, the values of the principal quantum number (n) continues to increase.
As the principal quantum number (n) increases, the orbital becomes farther away from the nucleus.
The higher energy orbital are always larger than the orbitals closer to the nucleus.
Hence, the 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.
Explanation:
Answer:
3.422 m/s^2
Explanation:
A useful relation is ...
v2^2 -v1^2 = 2ad
(25 m/s)^2 -(3 m/s)^2 = 2a(90 m)
(616 m^2/s^2)/(180 m) = a ≈ 3.422 m/s^2
The acceleration is about 3.422 m/s^2.
The induced current produced due to moving sliding rod having resistance 0.05 is 2.4 A.
Induced current:
Any change in the magnetic field associated with a coil of wire will cause an emf to be induced in the coil. This emf is called induced emf and if the conductor circuit is closed, current will also circulate through the circuit. This current is called induced current.
Given, length of sliding rod, l= 0.1 m
Magnetic field = 0.60T
Velocity = 2m/s
Resistance of the loop = 0.05
Emf Induced = Blv
induced current = Blv/R



so, the current produced in sliding rod moving withspeed of 2m/s in magnetic field 0.6 T and having resistance of loop 0.05, is 2.4 A
learn more about induced current:
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