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MakcuM [25]
4 years ago
8

The upward force on an airplane's wing is thrust.

Physics
1 answer:
kompoz [17]4 years ago
3 0

No.  'Thrust' is what most people in aviation call the force
that pushes the aircraft forward. 

The same people generally call the upward force on the wing "lift".

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2. Unless an object at rest is acted upon by a force, it stays at rest due to it's __________.
Leokris [45]

Inertia. (Newton's Laws of Motion)

5 0
4 years ago
Calculate the current in a circuit if 500 C of charge passes through it in 10 minutes. *
Sloan [31]

Answer:

Choice a. Approximately 0.83\; \rm A on average.

Explanation:

The electric current through a wire is the rate at which electric charge flows through a cross-section of this wire.

Assume that electric charge of size Q flowed through a wire cross-section over a period of time t. The average current in that wire would be:

\displaystyle I = \frac{Q}{t}.

For this question:

  • Q = 500\; \rm C, whereas
  • t = 10\; \rm \text{minutes}.

Therefore, the average current in this circuit would be:

\displaystyle I = \frac{Q}{t} = \frac{500\; \rm C}{10\; \text{minutes}} = 50\; \rm C /\text{minute}.

However, the units in the choices are all in \rm A (for Amperes.) One Ampere is equal to one \rm C / \text{second}. It will take some unit conversations to change the unit of I = 50\; \rm C/ \text{minute} (coulombs-per-minute) to coulombs-per-second.

\begin{aligned}I &= 50\; \rm C/ \text{minute} \\ &= \frac{50\; \rm C}{1\; \rm \text{minute}} \times \frac{1 \; \text{minute}}{60\; \rm \text{seconds}} \approx 0.83\; \rm C/ \text{second} = 0.83 \; \rm A\end{aligned}.

Hence, the most accurate choice here would be choice a.

7 0
3 years ago
an eskimo pushes a loaded sled with a mass of 300kg over the frictionless surface of hard-packed snow.he exerts a constant 170n
Shalnov [3]

Answer:

0.567 m/s²

Explanation:

Newton's second law:

∑F = ma

170 N = (300 kg) a

a = 0.567 m/s²

Round as needed.

3 0
3 years ago
Read 2 more answers
a charged particle traveling follows a straight path through crossed electric and magnetic fields if the strength of the magneti
kaheart [24]

Answer:

Explanation:

When a charged particle is moving in a straight line, means undeflected in a crossed magnetic and electric field, it means the net force on the charged particle is zero.

magnetic force is balanced by the electric force

q v B = q E

Where, q be the charge on the particle, v be the velocity, B be the strength of magnetic field, e be the strength of electric field.

So, B = E / v

8 0
3 years ago
HELP!!!
FinnZ [79.3K]
A and B i think is the answer
7 0
3 years ago
Read 2 more answers
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