Ask question

Ask question

All categories

3 years ago

8

A particular planet has a moment of inertia of 9.74 × 1037 kg•m2 and a mass of 5.98 × 1024 kg. Based on these values, what is th

e planet’s radius?

1 answer:

goldfiish [28.3K]3 years ago

4 0

Assuming the planet can be treated as a solid sphere, $I=\frac{2}{5}MR^2$

(9.74 x 10^37 kg-m²) = (2/5)(5.98 x 10^24 kg)R²

R = 6.38 x 10^6 m

You might be interested in

Something has a mass of 40 kg and a velocity of 1 m/s

lesantik [10]

m=40kg
v=1m/s

$\\ \sf\Rrightarrow K.E=\dfrac{1}{2}mv^2$

$\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(40)(1)^2$

$\\ \sf\Rrightarrow K.E=20J$

<h3>Part 2:-</h3>

m=80kg

$\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(80)(1)^2$

$\\ \sf\Rrightarrow K.E=40J$

Yes

6 0

3 years ago

Pls answerrr it's urgent!!!!!

lilavasa [31]

Explanation:

the average velocity of the car is 15 m/s example I have this on a test

6 0

2 years ago

What is a good way to study guys for a science test Im in need because I have a quiz tmrw

nikklg [1K]

Answer:

Space out your studying. Nate Kornell “definitely did cram” before big tests when he was a student. ...

Practice, practice, practice! ...

Don't just reread books and notes. ...

Test yourself. ...

Mistakes are okay — as long as you learn from them. ...

Mix it up. ...

Use pictures. ...

Find examples.

Explanation:

5 0

3 years ago

The students on the right are applying a force of 100 N to the right. This is shown by the red arrow. The students on the left a

Artyom0805 [142]

Answer:

A

Explanation:

suddenly part of the force pulling to the left is gone.

and now the force pulling to the right is stronger.

so, the rope will move to the right. and that is also the direction of the net force.

8 0

2 years ago

Read 2 more answers

The coefficient of kinetic friction between a suitcase and the floor is 2.76. if the suitcase has a mass of 71.5 kg, how far can

mihalych1998 [28]

suitcase can be pushed to a distance of 0.35 m

Explanation:

Work done= Ff d

w= 670 J

Ff= force of friction

d= distance

force of friction is given by Ff=μ mg

μ= coefficient of friction=2.76

m=mass=71.5 kg

so Ff= (2.76) (71.5) (9.8)

Ff=1934 N

so W= Ff d

670= 1934 d

d=0.35 m

8 0

3 years ago