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Eva8 [605]
3 years ago
8

A particular planet has a moment of inertia of 9.74 × 1037 kg•m2 and a mass of 5.98 × 1024 kg. Based on these values, what is th

e planet’s radius?
Physics
1 answer:
goldfiish [28.3K]3 years ago
4 0
Assuming the planet can be treated as a solid sphere,I=\frac{2}{5}MR^2

(9.74 x 10^37 kg-m²) = (2/5)(5.98 x 10^24 kg)R²

R = 6.38 x 10^6 m
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