A heat engine is a device that uses _____to produce useful work.
2 answers:
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Answer:
v=0.94 m/s
Explanation:
Given that
M= 5.67 kg
k= 150 N/m
m=1 kg
μ = 0.45
The maximum acceleration of upper block can be μ g.
a= μ g ( g = 10 m/s²)
The maximum acceleration of system will ω²X.
ω = natural frequency
X=maximum displacement
For top stop slipping
μ g =ω²X
We know for spring mass system natural frequency given as
By putting the values
ω = 4.47 rad/s
μ g =ω²X
By putting the values
0.45 x 10 = 4.47² X
X = 0.2 m
From energy conservation
150 x 0.2²=6.67 v²
v=0.94 m/s
This is the maximum speed of system.
Answer:
Velocidad final, V = 40 m/s
Explanation:
Dados los siguientes datos;
Aceleración = 5 m/s²
Velocidad inicial = 0 m/s (ya que comienza desde el reposo)
Tiempo = 8 segundos
Para encontrar la velocidad final, usaríamos la primera ecuación de movimiento;
Dónde;
- V es la velocidad final.
- U es la velocidad inicial.
- a es la aceleración.
- t es el tiempo medido en segundos.
Sustituyendo en la fórmula, tenemos;
<em>Velocidad final, V = 40 m/s</em>
Answer:
a) T = (281.47 i ^ + 714.56 j ^) N , b) F_net = (281.47 i ^ - 110.44 j ^) N ,
c) F = 281.70 N, d) θ = 338.58º , e) a = 3,588 m / s² , f) θ = 201.45º
Explanation:
For this exercise we will use Newton's second law on each axis
X axis
-Tₓ = m aₓ
Y Axisy
–W = m a_{y}
Let's use trigonometry to find the components of force
sin 21.5 = Tₓ / T
cos 21.5 = T_{y} / T
Tₓ = T sin 21.5
T_{y} = T cos 21.5
Tₓ = 768 sin 21.5 = 281.47 N
T_{y} = 768 cos 21.5 = 714.56 N
a) the force of the rope on Tarzan is
T = (281.47 i ^ + 714.56 j ^) N
b) The net force is the subtraction of the tension minus the weight of Tarzan
Y Axis F_net = 714.56 - 825 = -110.44 N
F_net = (281.47 i ^ - 110.44 j ^) N
c) Let's use Pythagoras' theorem
F = √ (Fₓ² + T_{y}²)
F = √ (281.47² + 110.44²)
F = 281.70 N
d) Let's use trigonometry
tan θ = F_{y} / Fₓ
θ = tan⁻¹ F_{y} / Fₓ
θ = tan⁻¹ (-110.44 / 281.47)
θ = -21.42º
This angle is average clockwise, for counterclockwise measurement
θ = 360 - 21.42
θ = 338.58º
Acceleration
X axis
Tₓ = m aₓ
aₓ = Tₓ / m
The mass of Tarzan is
m = W / g
m = 825 / 9.8 = 84.18 kg
aₓ = 281.47 / 84.18
aₓ = -3.34 m / s2
Y Axis
T_{y}-W = m a_{y}
a_{y} = (T_{y} -W) / m
a_{y} = (714.56-825) / 84.18
a_{y} = - 1,312 m / s²
Acceleration Module
a = √ aₓ² + a_{y}²
a = √ (3.34² +1.312²)
a = 3,588 m / s²
The angle
θ = tan⁻¹ a_{y} / aₓ
θ = tan⁻¹ (-1312 / -3.34)
θ = 21.45º
Notice that the two components of the acceleration are negative, so the angle is in the third quadrant, to measure from the x-axis
θ = 180 + 21.45
θ = 201.45º