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inn [45]
3 years ago
10

Question 3 of 10

Physics
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

c. earth is a satellite of the sun

Explanation:

a satellite is an object that moves around a larger object therefore the earth is a satellite of the sun

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Im going with B for transverse wave
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Coasting due west on your bicycle at 8 m/s, you encounter a sandy patch of road 7.2m
jeka57 [31]

Answer:

V = (v1 + v2) / 2 = (8 + 6.5) / 2 = 7.25 m/s     average speed

t = 7.2 / 7.25 = .993 sec      time to cross patch

a = (v2 - v1) / t = (6.5 - 8) / .993 = -1.51 m/s^2     or 1.5 m/s^2

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Read 2 more answers
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.220 T. If the kinetic energy of the electr
Gwar [14]

Answer:

971605.66\ \text{m/s}

25.1\ \mu\text{m}

Explanation:

m = Mass of electron = 9.11\times 10^{-31}\ \text{kg}

B = Magnetic field = 0.22 T

K = Kinetic energy of electron = 4.3\times 10^{-19}\ \text{J}

q = Charge = 1.6\times 10^{-19}\ \text{C}

v = Velocity of electron

r = Radius of curved path

Kinetic energy is given by

K=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{\dfrac{2K}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 4.3\times 10^{-19}}{9.11\times 10^{-31}}}\\\Rightarrow v=971605.66\ \text{m/s}

The speed of the electron is 971605.66\ \text{m/s}

The force balance of the system is given by

qvB=\dfrac{mv^2}{r}\\\Rightarrow r=\dfrac{mv}{qB}\\\Rightarrow r=\dfrac{9.11\times 10^{-31}\times 971605.66}{1.6\times 10^{-19}\times 0.22}\\\Rightarrow r=0.0000251=25.1\ \mu\text{m}

The radius of the curved path is 25.1\ \mu\text{m}

6 0
3 years ago
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