Answer:
d = 146.2 m
increase
Explanation:
Using Energy Balance:
U_i + W = U_f
K_i + U_gi + W = K_f + U_fg
0 + m*g*h + F*d = 0.5*m*v_f^2
(900)*(9.81)*(50 sin (5)) + 400*50 = 0.5*900*v_f^2
v_f^2 = 129.944
v_f = 11.4 m/s at the bottom of the hill
U_i + W = U_f
K_i + U_gi + W = K_f + U_fg
0.5*m*v_i^2 - F*d = 0
0.5*900*129.944 = 400*d
d = 146.19 m
part b
Heavier car will gain greater momentum at the bottom of the hill and attain a higher velocity at the bottom; hence, the distance will increase.
Answer: increase
I’m not sure but I think the answer is d but I’m not that sure
Drag from her armas would slow her down if she was spinning at a fast speed
It depends when you look at a pichture it could possibly help.