A function which is used to represent a problem, and which can be used to solve the problem, is called a

Mathematics

1 answer:

UkoKoshka [18]3 years ago

7 0

Answer:

I believe the answer is model

Hope this helps <3

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2. Graph each inequality on a number line:<br><br> 5x + 15 < 0

Georgia [21]

Answer:

x < -3

Step-by-step explanation:

1. To put this inequality on a number line, we first must solve it.

Step 1: Subtract 15 from both sides.

$5x + 15 - 15 < 0 - 15$

$5x < -15$

Step 2: Divide both sides by 5.

$\frac{5x}{5}$
$x < -3$

2. Now that we know x < -3, let's graph it!

Since it's less than, we make the number line point to the left, and we make the circle open.

3 0

2 years ago

adam bought a box of fruit that weighed 6 3/8 kilograms. If he bought a second box that weighed 7 25 kilograms, what is the comb

arlik [135]

Box 1 = 6 & 3/8 kilograms.
Box 2 = 7 & 2/8 kilograms.

6 & 3/8 + 7 &2/8 = 13 & 5/8 kilograms.

Therefore the combined weight of the boxes are 13 & 5/8 kilograms.

7 0

2 years ago

Find the third term in the expansion of (a+b)^9 in the simplest form

forsale [732]

Answer:

$The\ third\ term\ is\ \boxed{36a^7b^2}\\$

Step-by-step explanation:

$\left(\begin{array}{c}9\\ 1\end{array}\right)=\dfrac{9}{1} =9\\\\\left(\begin{array}{c}9\\ 2\end{array}\right)=\dfrac{9*8}{2*1} =36\\\\\\(a+b)^9=a^9+\left(\begin{array}{c}9\\ 1\end{array}\right)a^8b+\left(\begin{array}{c}9\\ 2\end{array}\right)a^7b^2+....+b^9\\\\\\The\ third\ term\ is\ \boxed{36a^7b^2}\\$