The 2nd choice is appropriate.
I got 20,737 but I could be wrong so I will attach my algorithm and work.
Length: 2w + 59
width: w
diagonal: (2w + 59) + 2 = 2w + 61
Length² + width² = diagonal²
(2w + 59)² + (w)² = (2w + 61)²
(4w² + 118w + 3481) + w² = 4w² + 122w + 3721
5w² + 118w + 3481 = 4w² + 122w + 3721
w² + 118w + 3481 = 122w + 3721
w² - 4w + 3481 = 3721
w² - 4w - 240 = 0
a = 1, b = -4, c = -240
w =
=
=
=
=
=
since width cannot be negative, disregard 1 - 2√61
w = 1 + 2√61 ≈ 16.62
Length: 2w + 59 = 2(1 + 2√61) + 59 = 2 + 4√61 + 59 = 61 + 4√61 ≈ 92.24
Answer: width = 16.62 in, length = 92.24 in
Answer:
Step-by-step explanation:
a)
428721
Place of 2's 10s and 10,000s
Therefore its value is 20 and 20,000
Product of the place value = 20 x 20,000 = 4,00,000
b)
37,20,861
Place of 7 is 1,00,000
Therefore the place value is 7,00,000
c)
Greatest 7 digit number is 99,99,999
Adding 1 to it = 99,99,999 + 1 = 1,00,00,000
d)
85642 = 80000 + 5000 + 600 + 40 +2
e)
round off 85642 to nearest thousand = 86,000