SOLUTION
The given expression is:
![-5\sqrt[]{147\times r^{13}\times s^8}](https://tex.z-dn.net/?f=-5%5Csqrt%5B%5D%7B147%5Ctimes%20r%5E%7B13%7D%5Ctimes%20s%5E8%7D)
Rewrite the expression
![-5\sqrt[]{49\times3\times r^{12}\times r^1\times s^{4\times2}}](https://tex.z-dn.net/?f=-5%5Csqrt%5B%5D%7B49%5Ctimes3%5Ctimes%20r%5E%7B12%7D%5Ctimes%20r%5E1%5Ctimes%20s%5E%7B4%5Ctimes2%7D%7D)
This further give
![\begin{gathered} -5\sqrt[]{49\times3\times(r^6)^2\times r^1\times(s^4)^2} \\ =-5\times7\times r^6\times s^4\sqrt[]{3\times r} \\ =-35r^6s^4\sqrt[]{3r} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20-5%5Csqrt%5B%5D%7B49%5Ctimes3%5Ctimes%28r%5E6%29%5E2%5Ctimes%20r%5E1%5Ctimes%28s%5E4%29%5E2%7D%20%5C%5C%20%3D-5%5Ctimes7%5Ctimes%20r%5E6%5Ctimes%20s%5E4%5Csqrt%5B%5D%7B3%5Ctimes%20r%7D%20%5C%5C%20%3D-35r%5E6s%5E4%5Csqrt%5B%5D%7B3r%7D%20%5Cend%7Bgathered%7D)
Therefore, the solution is
![-35r^6s^4\sqrt[]{3r}](https://tex.z-dn.net/?f=-35r%5E6s%5E4%5Csqrt%5B%5D%7B3r%7D)
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Hope this helps! :)
Answer:
Make a coordinate plane and you have to solve around the origin say 4,4 and 4,1.
Step-by-step explanation:
Answer:
a=8
b=17
Step-by-step explanation:
Isoceles means we will have 2 congruent sides in this triangle.
So it appears we are to assume it is sitting on its base which means that other side has measurement ax+9 as well
So we have the sum of the 3 sides is the perimeter.
That means we have the equation:
(ax+9)+(ax+9)+(4x+b)=20x+35
Combine like terms:
(a+a+4)x+(9+9+b)=20x+35
(2a+4)x+(18+b)=20x+35
This implies 2a+4=20 and 18+b=35.
2a+4=20
Subtract 4 on both sides:
2a=16
Divide both sides by 2:
a=8
18+b=35
Subtract 18 on both sides:
b=17
So a=8 and b=17.
