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3 years ago

14

You need to solve for X

1 answer:

sladkih [1.3K]3 years ago

7 0

These are similar triangles so proportions hold. the short side to the bottom side proportion must be the same in both triangles. to solve it

25/30 = 35/x. (25+10=35 is the side of the bigger triangle

cross multiply and solve for x
25x=1050
x=1050/25=42

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Please help :))

fredd [130]

Answer:

0.15

Step-by-step explanation:

Fp: frequency that the pitcher will throw exactly 4 pitches to a batter=15

Fa: frequency that the pitcher will throw any pitches to a batter=15+20+40+15+10=100

P=Fp/Fa=15/100=0.15

7 0

2 years ago

The sum of the two digits of a number is 9. If the tens digit is one-half the units digit, what is the number? Let t = the tens

soldi70 [24.7K]

The second condition tells you that $t$ is half the size of $u$ , so $t=\dfrac12u$ , which could be rewritten in several ways. In standard form, that would be $2t-u=0$ .

3 0

3 years ago

Read 2 more answers

Prove that the value of the expression: 17^5+17^4 is divisible by 18.

Rudik [331]

Answer:

17^5+17^4 = 17^4 * (17^1 + 1) = 17^4 * 18

Step-by-step explanation:

8 0

2 years ago

A bucket that weighs 4 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

jonny [76]

Answer:

2580 ft-lb

Step-by-step explanation:

Water leaks out of the bucket at a rate of $\frac{0.15 \mathrm{lb} / \mathrm{s}}{1.5 \mathrm{ft} / \mathrm{s}}=0.1 \mathrm{lb} / \mathrm{ft}$

Work done required to pull the bucket to the top of the well is given by integral

$W=\int_{a}^{b} F(x) dx$

Here, function $F(x)$ is the total weight of the bucket and water $x$ feet above the bottom of the well. That is,

$F(x)=4+(42-0.1 x)$

$=46-0.1x$

$a$ is the initial height and $b$ is the maximum height of well. That is,

$a=0 \text { and } b=60$

Find the work done as,

$W=\int_{a}^{b} F(x) d x$

$=\int_{0}^{60}(46-0.1 x) dx$

$&\left.=46x-0.05 x^{2}\right]_{0}^{60}$

$=(2760-180)-0[$

$=2580 \mathrm{ft}-\mathrm{lb}
$

Hence, the work done required to pull the bucket to the top of the well is $2580 \mathrm{ft}- \mathrm{lb}$

4 0

2 years ago

14. Let R^2 have inner product defined by ((x1,x2), (y,, y2)) 4x1y1 +9x2y2 A. Determine the norm of (-1,2) in this space B. Dete

Vitek1552 [10]

The norm of a vector $\vec x$ is equal to the square root of the inner product of $\vec x$ with itself.

a. $\|(-1,2)\|=\sqrt{\langle(-1,2),(-1,2)\rangle}=\sqrt{4(-1)^2+9(2)^2}=\sqrt{40}=2\sqrt{10}$

b. $\|(3,2)\|=\sqrt{\langle(3,2),(3,2)\rangle}=\sqrt{4(3)^2+9(2)^2}=\sqrt{72}=6\sqrt2$

7 0

3 years ago