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Flauer [41]
3 years ago
11

Rearrange a (q-c)=d to make q the subject

Mathematics
1 answer:
Andrej [43]3 years ago
3 0
To rearrange you must first simplify
aq-ac=d  
add ac to each side:
aq=d+ac
then divide by a:
q=(d/a)+c and this is your answer
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2 numbers total 47 and have a difference of 21 what are the two numbers
murzikaleks [220]

x+y = 47

x-y = 21

------------  add together

2x =68  divide by 2

x=34

x+y = 47

34+ y = 47

subtract 34 from each side

y = 13

the two numbers are 34 and 13


7 0
3 years ago
Bianca calculated the height of the equilateral triangle with side lengths of 10. Then, she used the formula for area of a trian
tekilochka [14]
2.9
30
1/2(2.9)30
the same. despite different formulas.
give me brainliest pls
6 0
3 years ago
Read 2 more answers
Whats the fraction 18/24 reduced to its lowest items?
asambeis [7]
Hello!

\sf Answer:

The fraction 18/24, reduced to its lowest terms, is: \boxed{3/4}
_____________________________

Divide both the numerator and the denominator by the GCD of 18 and 24, which is 6:

18 ÷ 6 = 3

24 ÷ 6 = 4

It's simplest form would be 3/4. This cannot be reduced further.
3 0
3 years ago
How do I solve for x here? Use the properties of logarithms to find a value for x. Assume a,b, and M are constants.
Leona [35]

Yes, you're right! The first step is rewriting the equation as

\ln(a) + \ln(b^x) = M

Subtract \ln(a) from both sides:

\ln(b^x) = M-\ln(a)

Use the property \ln(a^b) = b\ln(a) to rewrite the equation as

x\ln(b) = M-\ln(a)

Divide both sides by \ln(b)

x = \dfrac{M-\ln(a)}{\ln(b)}

Alternative strategy:

Consider both sides as exponents of e:

e^{\ln(ab^x)} = e^M

Use e^{\ln(x)} = x to write

ab^x = e^M

Divide both sides by a:

b^x = \dfrac{e^M}{a}

Consider the logarithm base b of both sides:

x = \log_b\left(\dfrac{e^M}{a}\right)

The two numbers are the same: you can check it using the rule for changing the base of logarithms

7 0
3 years ago
What are the factors of 6tu
creativ13 [48]
<span> </span><span>
Depending on the value of 't' and 'u', the numerical value of that expression
could have almost anything for factors. 

For example, if  't' happens to be 3 and 'u' happens to be 10, then  6tu = 180,
and the factors of  6tu  are

   1,   2,   3,  4,  5,  6,  9,  10,  12,  15,  18,  20,  30,  36,  45,  60,  90, and  180.

But that would only be temporary ... only as long as  t=3  and  u=10. 

The only factors you can always count on, that don't depend on the values
of  't'  and  'u', are

           1,  6,  t,  u,  6t,  6u,  tu,  and  6tu .
</span>
6 0
3 years ago
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