Answer:
none of them
Step-by-step explanation:
Two lines are perpendicular when satisfy the next equation: m1*m2 = -1, where m1 and m2 are the slopes o the lines.
line 1:
y – 1 = (x+2)
y = x + 3
slope of line 1 = 1
line 2:
y + 2 = –3(x – 4)
y + 2 =
-3*x + 12
y = -3*x + 10
slope of line 2 = -3
m1*m2 = 1*(-3
) = -3
They are not perpendicular
line 3:
y − 5 = 3(x + 11)
y − 5 = 3*x + 33
y = 3*x + 38
slope of line 3 = 3
m1*m3 = 1*3 = 3
They are not perpendicular
line 4:
y = -3x –
slope of line 4 = -3
m1*m4 = 1*(-3
) = -3
They are not perpendicular
line 5:
y = x – 2
slope of line 5 = 1
m1*m5 = 1*1 = 1
They are not perpendicular
line 6:
3x + y = 7
y = -3x + 7
slope of line 6 = -3
m1*m6 = 1*(-3
) = -3
They are not perpendicular
Katia and Thomasina play a computer game and record these scores. Katia: 8, 6, -4, -7, 2, 0, 3 Thomasina: -11, 0, 8, 7, 5, -7, 1
suter [353]
Answer:
Step-by-step explanation:
there is no factorization of y^2 -2y +35 in real numbers
Thomasina correctly determined two factors of 35 that differ by 2, but that is not what is needed here. For this problem, she needs two factors of 35 that have a sum of 2.* (There aren't any real-number factors that meet that condition.)
__
The factorization in complex numbers would be ...
= (y -1 -i√34)(y -1 +i√34)
_____
* Technically, she needs two factors of 35 with a sum of -2. Both factors would have to be negative.
The cosine of angle X is

By the Pythagorean theorem, we have

Then

Multiplying numerator and denominator by 2, we get
.
13ab^3(1+3ab) -ANSWER
You're factorising 13ab^3 from the expression - hope this helps:)
Answer:
4.8
Step-by-step explanation:
8 times .6 is 4.8
So 4.8 divided by .6 would be 8!
I hope that helps!