<span>Hope this helps
when </span>she<span> started with </span>5 feet<span>, </span>she then cuts<span> off 3 and </span><span>3/4 feet</span><span> to </span>make<span> a </span>hair bow, being left with 5<span> - </span><span>33/4</span><span> = 1</span>1<span>/4 </span>feet<span>. </span>Then she cuts<span> off </span>5/6 feet<span> to </span>make<span> a </span>border<span> on a </span>scrapbook page, being left with. 11<span>/4 - </span>5/6<span> = </span>5<span>/4 - </span>5/6<span>. = </span>15<span>/12 - </span>10<span>/12. = </span>5<span>/12 </span>feet<span>. If </span>she<span> needs to </span>cut<span> 2 </span>1/3-feet<span> pieces, </span>she<span> will need 2(</span>1/3<span>) = </span>2/3 feet<span>.</span>
Look at the picture below
Answer:
(1) B. f(x)->0 as x->∞, f(x)->∞ as x->-∞
(2) D. ![f(x)= 2^{-x}+5](https://tex.z-dn.net/?f=f%28x%29%3D%202%5E%7B-x%7D%2B5)
Step-by-step explanation:
. Given 0<b<1
'b' is between 0 and 1 so b should be a fraction
'b' is a fraction, so for positive value of x , the value of f(x) cannot be negative.
the graph of f(x) will goes close to 0 but it never cross x axis
So end behavior is f(x)->0 as x->∞
for negative values of x , the y value increases
So end behavior is f(x)->∞ as x->-∞
(2) f(x) = 2^x
When graph reflects across y axis, x becomes -x
so ![f(x)= 2^{-x}](https://tex.z-dn.net/?f=f%28x%29%3D%202%5E%7B-x%7D)
For translating up by 5 units we add 5 at the end
so ![f(x)= 2^{-x}+5](https://tex.z-dn.net/?f=f%28x%29%3D%202%5E%7B-x%7D%2B5)