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Mila [183]
3 years ago
10

Find the angle between the given vectors to the nearest tenth of a degree. u = (8, 4), v = (9, -9)

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0

Answer:

<em>71.6 degrees </em>

Step-by-step explanation:

The formula for calculating the angle between two vectors is expressed as;

u.v = |u||v|cos theta

u.v = (8, 4).(9, -9)

u.v = 8(9)+4(-9)

u.v = 72-36

u.v = 36

|u| = √8²+4²

|u| = √64+16

|u| = √80

|v| = √9²+(-9)²

|v| = √81+81

|v| = √162

36 = √80*√162 cos theta

36 = √12960 cos theta

36 = 113.84 cos theta

cos theta = 36/113.84

cos theta = 36/113.84

cos theta = 0.3162

theta = arccos (0.3162)

<em>theta = 71.6 degrees </em>

<em>Hence the angle between the given vectors is 71.6 degrees </em>

Simora [160]3 years ago
6 0

Answer:

71.6°

Step-by-step explanation:

arctan(4/8) - arctan(-9/9) = 26.57° - (-45°) ≈ 71.6°

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write the repeating number with 9 in the denominator

Step-by-step explanation:

Just write the repeating number over 9

i.e.

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5 0
3 years ago
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Divide 1.75 × 10^-2 by -7.3 × 10^-8. Express your answer in scientific notation. Round the coefficient to two decimal places.​
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Answer:

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Step-by-step explanation:

4 0
3 years ago
A frog is sitting exactly in the middle of a board that is five feet long. Every ten seconds he jumps one foot to the left or on
mart [117]

Answer:

Since the Frog makes a Jump every 10 seconds

   ( using the digits on a random number table )

  • It will take 7 jumps with 2 jumps in reverse direction i.e. either left or right for the frog to be off the board in 60 seconds
  • it will take 3 jumps in similar direction as well to get the frog off the board
  • also 5 jumps with 1 jump in the opposite direction is what it will take to get the frog off the board as well within the time frame of 60 seconds

Step-by-step explanation:

A frog sitting exactly in the middle of a board which is 5ft long : frog is 2.5 ft from the edge of the board

every 10 seconds the frog jumps ; L or R

If he jumps ; LLRLRL ( still on Board on the left-most square )

if he jumps ; LLRLL ( He is off the Board in fifty seconds )

Since the Frog makes a Jump every 10 seconds

   ( using the digits on a random number table )

  • It will take 7 jumps with 2 jumps in reverse direction i.e. either left or right for the frog to be off the board in 60 seconds
  • it will take 3 jumps in similar direction as well to get the frog off the board
  • also 5 jumps with 1 jump in the opposite direction is what it will take to get the frog off the board as well within the time frame of 60 seconds
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Answer:

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Murrr4er [49]

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x = 133/19 - 7



6 0
3 years ago
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