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4 years ago

How to find square root of 18

Mathematics

1 answer:

likoan [24]4 years ago

7 0

Answer:

There is a very complicated paper-and-pencil method to calculate the square root one digit at a time.

Step-by-step explanation:

We know that 4 is the first digit of our answer, so write it down.

Multiply the top number by the left number (4 x 4)

Write it down below the 18 and subtract (18 - 16 = 2)

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Which ordered pair is the solution to the system of equations below when using the matrix tool?

boyakko [2]

The second one y bc I did this test already

4 0

3 years ago

The amount of paper that the copy shop used this month was a 25% increase of the amount of paper they used last month. What perc

likoan [24]

Answer:

You didn't include any image here, but numerically, the amount of paper consumed this month is 125% compared to last month.

If last month's consumption is represented by 4 equal shapes, then the current month's consumption will be 5 shapes.

If last month's consumption is represented by 8 equal shapes, then the current month's consumption will be 10 shapes.

this pattern keeps repeating.

3 0

3 years ago

The voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has

ANTONII [103]

Answer:

The voltage in exponential form would be $(\frac{3}{5})^3$ .

The original voltage in the circuit is $\frac{3}{5}$ of a volt.

Step-by-step explanation:

Let x represent the original voltage.

We have been given that the voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has been reduced 3 times.

The original voltage multiplied by itself for 3 times would be $x\cdot x\cdot x=x^3$ .

Now, we will equate $x^3$ with 27/125 as:

$x^3=\frac{27}{125}$

We know that 27 is cube of 3 and 125 is cube of 5, so we can represent our equation as:

$x^3=\frac{3^3}{5^3}$

$x^3=(\frac{3}{5})^3$

Therefore, the voltage in exponential form would be $(\frac{3}{5})^3$

Now, we will take cube root of both sides to find original voltage in the circuit as:

$\sqrt[3]{x^3} =\sqrt[3]{(\frac{3}{5})^3}$

Using property $\sqrt[n]{a^n} =a$ , we will get:

$x =\frac{3}{5}$

Therefore, the original voltage in the circuit is $\frac{3}{5}$ of a volt.

6 0

4 years ago

Tell weather the two rates form a proportion. help

Sindrei [870]

7/9 = 42/54...when 42/54 reduces, it becomes 7/9...so this is proportional because proportions are nothing but equivalent fractions.

u could also check it this way...
12/21 = 15/24
cross multiply
(21)(15) = (12)(24)
315 = 288.....these do not equal and are therefore, not proportionate

440/4 = 300/3
110 = 100....not equal, so not proportionate

120/5 = 88/4
24 = 22.....not proportionate

66/82 = 99/123
0.804 = 0.804.......these are proportional

68/172 = 43/123
0.395 = 0.349......nope, not proportional

6 0

3 years ago

Violet was carrying around the steps to solve square root of 3x plus 1 = 4. On her way through the Math Factory, Violet dropped

lutik1710 [3]

Answer:

Step-by-step explanation:

solve square root of 3x plus 1 = 4:

D is correct and results in 3x + 1 = 16; after this we subtract 1 from both sides and end up with 3x = 15, or x = 5.

7 0

3 years ago

Read 2 more answers