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ivanzaharov [21]
4 years ago
10

A car is purchased for

Mathematics
2 answers:
Mila [183]4 years ago
8 0
$23,500 x .35= $8,225
$23,500-$8,225=$15,275 (year one)

$15,275 x .35= $5,346.25
$15,275-$5,346.25=$9928.75 (year two)

$9928.75 x .35= $3,475.06
$9,928.75-$3,475.06=$6,453.69 (year three)

$6,453.69 x .35=$2258.79
$6,453.69-$2,258.79=$4,194.90 (after year 4)

=$4,194.90

Leto [7]4 years ago
7 0
(using a calculator), do $23,500 times by (0.75)^4 (to the power of)
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<em>Note: I am assuming the first equation is:</em>

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Answer:

The solution to the system of equations is:

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Therefore, the x-coordinate of the solution of the system

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Step-by-step explanation:

Given the system of equations

\begin{bmatrix}x+y=34\\ x-y=-38\end{bmatrix}

subtracting the equations

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\underline{x+y=34}

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solve -2y for y

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Divide both sides by -2

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Subtract 36 from both sides

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Simplify

x=-2

Thus, the solution to the system of equations is:

(x, y) = (-2, 36)

Therefore, the x-coordinate of the solution of the system

x = -2

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