Question

Constructive proof: There exists an integer x such that: (x^3)/5 > x^2

Answer 1

Answer:

$x>5$

Step-by-step explanation:

We are asked to find an integer x such that $\frac{x^3}{5}>x^2$.

First of all, we will multiply both sides of inequality by 5.

$\frac{x^3}{5}>x^2$  

$\frac{x^3}{5}*5>5*x^2$  

$x^3>5x^2$  

Divide both sides by $x^2$:

$\frac{x^3}{x^2}>\frac{5x^2}{x^2}$

$x>5$

Therefore, the value of x is any number greater than 5.