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g100num [7]
3 years ago
14

Midpoint of (-3,2) (3,2)

Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer: (0, 2)

Step-by-step explanation:

Do (x1+x2/2, y1+y2/2) as your formula to find the midpoints. -3+3/2=0 and 2+2/2=2 so the midpoint is (0, 2). Hope this helps, have a blessed and wonderful day as well as a safe one and stay healthy!

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46.The function f graphed above is the function f(x) = log2(x) + 2 for x > 0. Find a formula for the inverse of this function
pantera1 [17]

Answer:

The inverse for log₂(x) + 2  is - log₂x + 2.

Step-by-step explanation:

Given that

f(x) = log₂(x) + 2

Now to find the inverse of any function we put we replace x by 1/x.

f(x) = log₂(x) + 2

f(1/x) =g(x)= log₂(1/x) + 2

As we know that

log₂(a/b) = log₂a - log₂b

g(x) = log₂1 - log₂x + 2

We know that  log₂1 = 0

g(x) = 0 - log₂x + 2

g(x) =  - log₂x + 2

So the inverse for log₂(x) + 2  is - log₂x + 2.

3 0
3 years ago
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Softa [21]
180^o-112^o=68^o

\left\{\begin{array}{ccc}2x+3y=68&|\cdot(-15)\\30x+11y=112\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-30x-45y=-1020\\30x+11y=112\end{array}\right}\\.\ \ \ \ \ \ \ -34y=-908\ \ \ |:(-34)\\\\.\ \ \ \ \ \ \ \ \ \ \  y=\dfrac{908}{34}\to y=\dfrac{454}{17}\\\\2x+3\cdot\dfrac{454}{17}=68\ \ \ \ |\cdot17\\\\34x+1362=1156\ \ \ \ |-1362\\34x=-206\ \ \ \ |:34\\\\x=-\dfrac{206}{34}\to x=-\dfrac{103}{17}\\\\  \left\{\begin{array}{ccc}x=-\dfrac{103}{17}\\\\y=\dfrac{454}{17}\end{array}\right
8 0
3 years ago
A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari
guajiro [1.7K]

Answer:

a

The null hypothesis is  H_o :  \sigma^2_1 = \sigma^2 _2

The alternative hypothesis is H_a :  \sigma_1 ^2 > \sigma^2_2

b

F_{critical} = 1.8608

c

F = 2.9085

d

    The decision rule is  

Reject the null hypothesis

e

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

 The first sample size is  n_1 = 30

 The sample variance for elementary school is  s^2_1 = 8324

 The second sample size is  n_2 = 30

  The sample variance for the secondary school is  s^2_2 = 2862

   The significance level is  \alpha = 0.05

The null hypothesis is  H_o :  \sigma^2_1 = \sigma^2 _2

The alternative hypothesis is H_a :  \sigma_1 ^2 > \sigma^2_2

Generally from the F statistics table  the critical value of \alpha = 0.05 at first and  second degree of freedom df_1 = n_1 - 1 = 30 - 1 = 29 and  df_2 = n_2 - 1 = 30 - 1 = 29 is  

         F_{critical} = 1.8608

Generally the test statistics is mathematically represented as

       F = \frac{s_1^2 }{s_2^2}

=>   F = \frac{8324 }{2862}

=>   F = 2.9085

Generally from the value obtained we see that  F >  F_{critical } Hence

   The decision rule is  

Reject the null hypothesis

    The conclusion is  

  There is sufficient evidence to support the researchers claim

   

4 0
3 years ago
One minute is 1/60 of an hour. What part of an hour is 12 minutes?
Alla [95]
2/10ths of an hour. You do 12/60 and get 0.2
7 0
3 years ago
Read 2 more answers
I need help with this one
Vesna [10]

Answer:

8

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
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