The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
40
Step-by-step explanation:
6% of number = 6/100 × x = 6x/100 = 3x/50
Sum of the number and 6% of itself = 42.4
x + (3x/50) = 42.4
(50x+3x)/50 = 42.4
53x = 42.4 × 50
53x = 2120
x = 2120/53
x = 40
Answer:
If 30 unicorns out of 300 walk away then it will be 300-30=270 unicorns left.
If 50 dragons fly away out of 200 then it will be 200-50=150.
Therefore there are 270 unicorns and 150 dragons left.
I hope this helps you...Thank you...
C is the answer hope that helps have a good day
