Answer:
The minimum score required for recruitment is 668.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Top 4%
A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?
Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.




Rounded to the nearest whole number, 668
The minimum score required for recruitment is 668.
Answer:
Area of sector bounded by angle = 100.37 ft² (Approx.)
Step-by-step explanation:
Given:
Radius of a circle = 12 feet
Arc angle θ = 80°
Find:
Area of sector bounded by angle
Computation:
Area of sector bounded by angle = [θ/360][πr²]
Area of sector bounded by angle = [80/360][(3.14)(12)²]
Area of sector bounded by angle =[0.22][(3.14)(144)]
Area of sector bounded by angle = [0.22][452.16]
Area of sector bounded by angle = 100.37 ft² (Approx.)
Answer:
7 units
Step-by-step explanation:
To find the distance between a pair of points, use the distance formula,
. Substitute the x and y values of (5,5) and (5, -2) into the formula and simplify:

So, the answer is 7 units.
Answer:
11 speakers
Step-by-step explanation:
2 3/4 ÷ 1/4
11/4 ÷ 1/4
11/4 x 4/1 = 44/4 = 11
If RY + YC = RC
7x+4=10x-2
3x=6
x=2
18+18=36=RC
The value of RC is 36