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3 years ago

How to write 1,010,101.101 in expanded form

Mathematics

1 answer:

grigory [225]3 years ago

7 0

1,000,000 + 10,000 + 100 + 1 + 0.1 + 0.001

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Solving Linear Equations: Variables on Both Sides I really need this please!

damaskus [11]

Answer: x=-2/3

Explanation: Heres what my calculator says!
After you divide it will give you -2/3 :)

4 0

2 years ago

I need help on this question

vodka [1.7K]

Answer

Arc EF = 52°

Arc HD = 142°

Angle HGF = 128°

Explanation

To solve for the unknown angles, we need to first solve for x

To do that, we need to first note that the sum of angles on a straight line is 180°

So,

Angle HCG + Angle HCD = 180° (Sum of angles on a straight line)

Angle HCG = 2x

Angle HCD = 6x + 28°

Angle HCG + Angle HCD = 180°

2x + 6x + 28° = 180°

8x + 28° = 180°

8x = 180° - 28°

8x = 152°

Divide both sides by 8

(8x/8) = (152°/8)

x = 19°

Angle HCG = 2x = 2 (19°) = 38°

Angle HCD = 6x + 28° = 6(19°) + 28° = 142°

So, we can solve for the rest now

Arc EF = Angle ECF

= 90° - Angle ECD

Angle ECD = Angle HCG = 38° (Vertically opposite angles are equal)

Arc EF = Angle ECF

= 90° - Angle ECD

= 90° - 38°

= 52°

Arc HD = Angle HCD = 142°

Angle HGF = Angle HCG + Angle GCF = 38° + 90° = 128°

Hope this Helps!!!

6 0

1 year ago

Find the mean of the data in the dot plot below.<br> jokers

galben [10]

There is no dot plot ?

6 0

3 years ago

$4000 is invested in a mutual fund that pays annual interest compounded quarterly for 15 years. What annual interest is needed t

Neporo4naja [7]

Answer:

The interest needed to reach that value of $6000 is 2.75%

Step-by-step explanation:

Given as :

The principal that invested in mutual fund = p = $4000

The time period = t = 15 years

The Amount after 15 years = A = $6000

Let The interest needed to reach that value = r%

Now, According to question

<u>From Compound Interest method</u>

Amount = principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, $6000 = $4000 × $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $\dfrac{6000}{4000}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

Or, $\frac{3}{2}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, 1.5 = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $1.5^{\frac{1}{15}}$ = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 - 1 = $\dfrac{r}{100}$

or, 0.0275 = $\dfrac{r}{100}$

∴ r = 0.0275 × 100

I.e r = 2.75

So, The interest needed to reach that value = r = 2.75%

Hence,The interest needed to reach that value of $6000 is 2.75% Answer

3 0

3 years ago

If the length of a rectangle is increased by 20% and the width of the rectangle is decreased by 10%, what is the percent increas

adell [148]

I believe it would be 10%

8 0

2 years ago