Answer:
The median is 6. The Mean Absolute Deviation is 1.88. The range is 10. I believe the IQR is 5.
Step-by-step explanation:
the median is just the number that falls in the center of a data set. The Mean Absolute Deviation is the distance of the data points from the mean. So, find the sum of the differences of each data point from the mean and divide it by the number of data points. Range is the difference between the smallest and largest values in a data set. The interquartile range is the middle of the data. it is a measure of how widely the middle half of the data is spread around the median.
Answer:
the width of a rectangular is 3 cm
Step-by-step explanation:
Length L = 10 cm
Perimeter P = 26 cm
Width W = ?
perimeter = 2L + 2W
26 = 2(10) + 2W
26 - 20 = 2W
6 = 2W
W = 6 / 2
W = 3 cm
therefore, the width of a rectangular is 3 cm
Answer:
![y + 3 = -1\frac{3}{5}[x - 2]\:or\:y - 5 = -1\frac{3}{5}[x + 3]](https://tex.z-dn.net/?f=y%20%2B%203%20%3D%20-1%5Cfrac%7B3%7D%7B5%7D%5Bx%20-%202%5D%5C%3Aor%5C%3Ay%20-%205%20%3D%20-1%5Cfrac%7B3%7D%7B5%7D%5Bx%20%2B%203%5D)
Step-by-step explanation:
First, find the <em>rate of</em><em> </em><em>change</em><em> </em>[<em>slope</em>]:
Now input the slope into the Point-Slope Formula. In this formula, all negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT signs:
![y - y_1 = m[x - x_1]](https://tex.z-dn.net/?f=y%20-%20y_1%20%3D%20m%5Bx%20-%20x_1%5D)
I am joyous to assist you anytime.
Student Tickets - x-64
Adult Tickets - x
x+x-64=386
2x=450
x=225
225 adult tickets were sold,
161 student tickets were sold.
Hope that helps!
The error interval for x is 3.65,3.74.
Given that,
- The number rounded to one decimal place is 3.7.
Now based on the above information, the number should be more than or equivalent to 5 at the n+1 place
- Like 3.65, 3.66, 3.67, 3.68 till 3.74
Based on the above information, we can conclude that the error interval for x is 3.65,3.74.
Learn more: brainly.com/question/17429689
