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3 years ago

IM TIMED PLEASE HELP ME please help math question

Mathematics

2 answers:

adell [148]3 years ago

8 0

Answer: D.

If you substitute the x = 9 into the first equation it will look like this:
2y = (9) - 6
Then solve for y,
2y = 3
y = 3/2

Therefore, the correct answer would be D. (9, 3/2)
This is because ordered pairs are (x,y) and x = 9 and y = 3/2

I hope this helps!!
- Kay :)

Tom [10]3 years ago

3 0

Answer is b because if you do it, it is. I am dum but that doesent matter.

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Complete the following sentences to compare the two functions. Over the interval [2, 6], the average rate of change of v is the

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2 years ago

Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]

agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

$cot \theta =\frac{1 }{tan \theta}$ so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = $\frac{\mathrm{d} \left (9t +9/tan(t/2) \right )}{\mathrm{d} t}$ = $\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9 \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}$

Equating to 0 and solving gives

$\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9 \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0$

$t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}$

Where n $_i$ is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2) = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0

4 years ago

4 log x = 4<br><br> What’s The Answer To This ?

Zolol [24]

Answer:

Step-by-step explanation:

6 0

4 years ago

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Nehal is a real estate developer, and he is designing a new neighborhood. The neighborhood will have four streets, each of which

ololo11 [35]

Answer:

240 houses

Step-by-step explanation:

Given that:

Number of streets = 4

Length of each street = 3/4 miles long

Street is divided into lots with one house built per lot

1 mile = 5289 feets

3/4 miles = (3/4) * 5280 = 3960 feets

Hence, street is 3960 feets long

Since each lot must have at least 65 feet frontage along the street:

Number of lots per street :

Length of street / frontage length

3960 ft / 65 ft = 60.92

Hence, maximum number of lots per street = 60 lots per street

Maximum number of houses in New neighborhoods :

Number of lots per street × number of streets

= 60 × 4

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4 0

3 years ago

Pls help me help me pls

grin007 [14]

Answer:

Point B

Step-by-step explanation:

Lines given:

y= 2/5x - 1/2
y= -1/3x +2/3

x coordinate of intersection of given lines is:

2/5x - 1/2= -1/3x+2/3
2/5x+1/3x= 2/3 +1/2
6/15x+5/15x= 4/6+3/6
11/15x=7/6
x= 7*15/11*6
x= 35/22

For this value of x, the value of y is:

y= 2/5*35/22 - 1/2
y=14/22- 1/2
y= 3/22

As per graph point (35/22, 3/22) is point B

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3 years ago