The length of the AB is 22 units if the length of AC is 44 units and DB is the median of the triangle.
<h3>What is the triangle?</h3>
The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.
The figure is missing.
The figure is attached to the picture, please refer to the picture.
We have a triangle shown in the picture.
As we know, the median bisects the side length into two equal parts.
AB = AC/2
AC = 44 units
AB = 44/2
AB = 22 units
Thus, the length of the AB is 22 units if the length of AC is 44 units and DB is the median of the triangle.
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Answer:
2 solutions
Step-by-step explanation:
2 solutions
3/4 - i
/4
3/4 + i/4
9514 1404 393
Answer:
-3 ≤ x ≤ 19/3
Step-by-step explanation:
This inequality can be resolved to a compound inequality:
-7 ≤ (3x -5)/2 ≤ 7
Multiply all parts by 2.
-14 ≤ 3x -5 ≤ 14
Add 5 to all parts.
-9 ≤ 3x ≤ 19
Divide all parts by 3.
-3 ≤ x ≤ 19/3
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<em>Additional comment</em>
If you subtract 7 from both sides of the given inequality, it becomes ...
|(3x -5)/2| -7 ≤ 0
Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.
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For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...
|f(x)| < (some number) . . . . or ≤
If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:
|f(x)| > g(x) ⇒ f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0
Any solutions to these inequalities must respect their domains.
