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3 years ago

PLEASE HELP! THANKS!

2 answers:

8 0

If you add everything up then
14x-2=180
14x=182
x= 13

So the angles would equal
2(13)+1= 27
3(13)-3= 36
9(13)= 117
The angles are 27 36 and 117
Which makes the smallest angle 27 which is B.

Misha Larkins [42]3 years ago

7 0

You first have to know that the measure of the three angles of a triangle= 180 add the terms and equal them to 180 2x+1 + 3x-3 =9x= 180 14x-2 = 180 14x= 182 x=13 This is not what you are looking for, you need to substitute 13 in the original measures 2 (13) +1= 27 degrees 3(13) -3= 36 degrees 9 (13) = 117 degrees therefore the smallest angle is 27 degrees if you add all three angle measure it will = 180 degrees Hope this helps you

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polet [3.4K]

Answer:

The answer would not be A. It is B

Step-by-step explanation:

Because you are subtracting the equations, on the right side of the equal sign, you are subtracting -5 from 7. This is 7-(-5), which is equal to 7+5=12, not -12.

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3 years ago

What is x^2=7x number 9

ipn [44]

Let's do this in steps, show your work!

#1. We need to move all terms to one side.

x^2 - 7x = 0

#2. Then factor out the common term x.

x(x - 7) = 0.

#3. Simplify to get..

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3 years ago

35 multiplied by the quantity r less than 45

Reil [10]

Hello There!

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3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

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Korolek [52]

Answer

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7 0

1 year ago