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2 years ago

How do you find the foci of an ellipse?

Mathematics

1 answer:

labwork [276]2 years ago

7 0

Answer:

Use the formula

Step-by-step explanation:

c2=a2−b2...The formula generally associated with the focus of an ellipse is c2=a2−b2 where c is the distance from the focus to center , a is the distance from the center to a vertex and b is the distance from the center to a co-vetex .

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15. PLEASE HELP ME

Nana76 [90]

Surface Area=7238in^2

We know

$\boxed{\sf Surface\:area=4\pi r^2}$

$\\ \sf\longmapsto 4\pi r^2=7238$

$\\ \sf\longmapsto 4\times \dfrac{22}{7}r^2=7238$

$\\ \sf\longmapsto r^2=\dfrac{7238\times 7}{88}$

$\\ \sf\longmapsto r^2=\dfrac{5066}{88}$

$\\ \sf\longmapsto r^2=575.75$

$\\ \sf\longmapsto r^2\approx576$

$\\ \sf\longmapsto r\approx\sqrt{576}$

$\\ \sf\longmapsto r\approx24in$

<h3>Option b is coreect</h3>

4 0

2 years ago

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RUDIKE [14]

Answer:

the answers are A, B, C, and F

Step-by-step explanation:

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3 years ago

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Write an equation for the perimeter of the rectangle

jeka94

Answer:

Area = 2(5x - 4) + 2(5x)

Step-by-step explanation:

Perimeter is the sum of twice the width and twice the length of the rectangle. And since the question is asking us for an equation, we need to write, Area = 2(5x - 4) + 2(5x). When you are required to find the value of x with a given area, just plug that area into the equation, distribute, and simplify to get x.

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2 years ago

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22x – 54 + 5.736x^4 - 2x^2<br> Standard form

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Answer:

5.736x^4 - 2x^2 +22x - 54

Step-by-step explanation:

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2 years ago

What is the Constant in <br> 3x + 7

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