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2 years ago

How do you find the foci of an ellipse?

Mathematics

1 answer:

labwork [276]2 years ago

7 0

Answer:

Use the formula

Step-by-step explanation:

c2=a2−b2...The formula generally associated with the focus of an ellipse is c2=a2−b2 where c is the distance from the focus to center , a is the distance from the center to a vertex and b is the distance from the center to a co-vetex .

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What is the product

djverab [1.8K]

Answer:

The product of given matrix is $AB=\begin{pmatrix}7\\ 4\\ 2\end{pmatrix}$

Step-by-step explanation:

Given : Two matrix

$A=\begin{pmatrix}3&6&1\\ 2&4&0\\ 0&6&2\end{pmatrix}$

and $B=\begin{pmatrix}2\\ \:0\\ \:1\end{pmatrix}$

We have to find the product of given matrix

$AB=\begin{pmatrix}3&6&1\\ 2&4&0\\ 0&6&2\end{pmatrix}\begin{pmatrix}2\\ 0\\ 1\end{pmatrix}$

Multiply the rows of first matrix by the columns of second matrix , we have,

$\begin{pmatrix}3&6&1\end{pmatrix}\begin{pmatrix}2\\ 0\\ 1\end{pmatrix}=3\cdot \:2+6\cdot \:0+1\cdot \:1$

$\begin{pmatrix}2&4&0\end{pmatrix}\begin{pmatrix}2\\ 0\\ 1\end{pmatrix}=2\cdot \:2+4\cdot \:0+0\cdot \:1$

$\begin{pmatrix}0&6&2\end{pmatrix}\begin{pmatrix}2\\ 0\\ 1\end{pmatrix}=0\cdot \:2+6\cdot \:0+2\cdot \:1$

$=\begin{pmatrix}3\cdot \:2+6\cdot \:0+1\cdot \:1\\ 2\cdot \:2+4\cdot \:0+0\cdot \:1\\ 0\cdot \:2+6\cdot \:0+2\cdot \:1\end{pmatrix}$

On , simplifying , we get,

$AB=\begin{pmatrix}7\\ 4\\ 2\end{pmatrix}$

Thus, the product of given matrix is $AB=\begin{pmatrix}7\\ 4\\ 2\end{pmatrix}$

4 0

2 years ago

Read 2 more answers

Steve washed 15 cars in 3 hours.how many cars can he wash in 7 hours?

DanielleElmas [232]

35 Cars because, if you times 3 by 5 it equals 15 which means that 1 hour equals 5 cars. So you times 7 by 5 and that will give you the amount of cars that were washed.

3 0

3 years ago

They won 3 out of every 4 home games and 2 out of every 3 away game. All together they won 40 more games than they lost. If they

lina2011 [118]

See https://web2.0calc.com/questions/help-please_82538.

5 0

3 years ago

A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

$^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : Total multiple-choice questions = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= $^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84$

No. of ways to answer 4 open-ended problems

= $^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15$

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= $84\times15=1260$

Hence, the correct answer is option A) 1260

5 0

3 years ago

50 POINTS!!! I WILL GIVE BRAINLIEST TO WHOEVER SHOWS STEPS! THANK YOU!:)))

taurus [48]

Answer:

Step-by-step explanation:

If you have something that says it is the f(x) or just f(something) then that is just telling you what the x equals. In this case, x=4 so you plug that into the equation.

This gives you f(4)=4(4)+7. From here, you will use the order of operations to solve.

f(4)=4*4+7

f(4)=16+7

f(4)=23

8 0

3 years ago

Read 2 more answers