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Furkat [3]
3 years ago
10

three vertices of a rectangle abcd are A(3,1) B(-3,1) and C(-3,3). find the fourth vertex and the area of the rectangle​

Mathematics
2 answers:
vichka [17]3 years ago
7 0

Answer:

The fourth vertex of the Rectangle ABCD is D ( 3 , 3 ).

The area of the rectangle ABCD:

length *  breadth

= 6 * 3

= 18 cm²

Hope the answer was helpful!!

If you liked t, please don't forget to mark it as Brainliest!!

Regards..

eimsori [14]3 years ago
5 0

<u>Answer: </u>

The Fourth vertex of the rectangle ABCD is (3, 3) and the area of the rectangle is 12 unit.

<u>Solution: </u>

Given three vertices of a rectangle are

A= (3, 1)

B= (-3, 1)

C= (-3, 3)  

Step 1:

The graph for this sum is attached below.

By looking at the graph we see that coordinates of D are (3, 3)  

We found the fourth vertex and now we can find the Area of rectangle.

Step 2:

The distance between B and C

We know the co-ordinates of B and C are B = (-3, 1) and C= (-3, 3)  

BC= (-3+3) + (3-1) = 2

Step 3:

The distance between D and C

We know the co-ordinates of D and C are (3, 3) and C= (-3, 3)  

DC= (-3-3) + (3-3) = 6

Step 4:

Area of ABCD rectangle = length \times breadth = DC \times BC

= 6 × 2  = 12 units  

Therefore area of Rectangle is 12 cm.

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The missing values are 28° and 62°

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