Ask question

Ask question

All categories

3 years ago

11

Alex's work for the following quiz problem is as follows: Is Alex correct? if it's incorrect, what is the correct solution?

1 answer:

exis [7]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

$\sqrt{10}$ and $\sqrt{5}$ cannot be simplified as they are already in simplest form.

Note that $\sqrt{10}$ + $\sqrt{5}$ ≠ $\sqrt{15}$

Thus

2 $\sqrt{10}$ + 5 $\sqrt{5}$ ← cannot be simplified any further

You might be interested in

Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations. (-4, 9), (0,

Tresset [83]

Answer:

$\boxed{y=2x^2+4x-7}$

Step-by-step explanation:

Let the quadratic function be

$y=ax^2+bx+c$

We substitute $(-4,9)$ into the equation to obtain;

$9=a(-4)^2+b(-4)+c$

$\Rightarrow 9=16a-4b+c---(1)$

We substitute $(0,-7)$ to obtain;

$-7=a(0)^2+b(0)^2+c$

$\Rightarrow c=-7---(2)$

We finally substitute $(1,-1)$ to obtain;

$-1=a(1)^2+b(1)^2+c$

$\Rightarrow -1=a+b+c---(3)$

We put equation (2) into equation (1) to get;

$9=16a-4b-7$

$16a-4b=16$

$\Rightarrow 4a-b=4---(4)$

$\Rightarrow -1=a+b-7$

$\Rightarrow a+b=6---(5)$

We add equation (4) and (5) to get;

$4a+a=6+4$

$\Rightarrow 5a=10$

$\Rightarrow a=2$

We put $a=2$ into equation (5) to get;

$2+b=6$

$\Rightarrow b=6-2$

$\Rightarrow b=4$

The reqiured quadratic function is

$y=2x^2+4x-7$

7 0

3 years ago

• To round a number, look at the digit to the right of the

nadya68 [22]

Answer:

2. A) 37 B)160 C) 110

The tens digit is 10,20,30,40,50,60,70,80,90. Two away to the left of a decimal point.

3. A)730 B) 675 C)1930

The hundreds digit is three from the left of a decimal point.

4. A) 0.40 B)74.60 C)15.20

The tenth is one away to the right of the decimal.

5. A)1.210 B) 3.430 C)0.350

The hundreth is two away to the right of the decimal point.

Explanation:

If it is above 5 you bring the digit before it up by one, if it is under 5 you bring the digit that is under 5 to zero.

8 0

3 years ago

A factory begins the day with 6,000 packaged light bulbs. the machines in the factory can package 1,200 light bulbs every hour f

Alex_Xolod [135]

Answer:

If the factory starts with 6,000 packaged light bulbs at the beginning of the day, and the factory produces 1,200 light bulbs every hour for the next 5 hours then in 5 hours there will be 6,000 light bulbs.

6,000 + (1,200 x 5) = ?
6,000 + 6,000 = ?
? = 12,000 lightbulbs

Step-by-step explanation:

Have a great rest of your day
#TheWizzer

5 0

2 years ago

.................................

Degger [83]

Answer: what ???? lol

3 0

3 years ago

Celeste makes a conjecture that the perimeter of a square whose sides are an odd

xxTIMURxx [149]

Answer:

top left

Step-by-step explanation:

8 0

3 years ago