Answer:
The initial speed of the car was 80 ft/s.
Step-by-step explanation:
The deceleration is the rate at which the car speed decreases. In this case the speed of the car goes all the way down to 0 ft/s and in order to do that it travelled 50 ft. So we will call the initial speed at which the car started to brake "v_0" and use Torricelli's equation to find it. The equation is given by:
v^2 = (v_0)^2 + 2*a*S
Where v is the final speed, v_0 is the initial speed, a is the rate of acceleration and S is the space travelled. Using the values that the problem gave to us we have:
0^2 = (v_0)^2 - 2*64*50
0 = (v_0)^2 - 6400
(v_0)^2 = 6400
v_0 = sqrt(6400) = 80 ft/s
Notice that in this case "a" was negative, since the car was decelerating instead of accelerating.
The initial speed of the car was 80 ft/s.
Answer:
they are = to each other
Step-by-step explanation:
Graph 1: y= -3/4, which means its (x,y) coordinate is (0, -3/4).
Graph 2: y= 3/4, which means its (x,y) coordinate is (0, 3/4).
Graph 1 would be the point -3/4 on the y-axis, while graph 2 would be the point 3/4 on the y-axis.
Therefore, graph 1 and graph 2 are symmetrical about the x-axis.
Hope this would help~
