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Morgarella [4.7K]
1 year ago
15

A factory begins the day with 6,000 packaged light bulbs. the machines in the factory can package 1,200 light bulbs every hour f

or the next 5 hours.
Mathematics
1 answer:
Alex_Xolod [135]1 year ago
5 0

Answer:

If the factory starts with 6,000 packaged light bulbs at the beginning of the day, and the factory produces 1,200 light bulbs every hour for the next 5 hours then in 5 hours there will be 6,000 light bulbs.




6,000 + (1,200 x 5) = ?
6,000 + 6,000 = ?
? = 12,000 lightbulbs











Step-by-step explanation:

Have a great rest of your day
#TheWizzer

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3x2 - 2x = 0<br> Factorise and solve
malfutka [58]

 Solve  :    3x-2 = 0  

Add  2  to both sides of the equation :  

                     3x = 2

Divide both sides of the equation by 3:

                    x = 2/3 = 0.667

Two solutions were found :

x = 2/3 = 0.667

x = 0

hope this helped

6 0
3 years ago
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The lowest number is 11 the range is 13 and the median is 17 what are the 3 numbers
11Alexandr11 [23.1K]

Answer:

11, 17, and 28.

Step-by-step explanation:

x, y, z\\

Lowest number is x

Median is y

Highest number is z

x=11\\y=17\\\\z-x=17\\z-11=17\\z-11+11=17+11\\z=28\\\\x=11\\y=17\\z=28\\\\11, 17, 28

3 0
3 years ago
One of the legs of a right triangle is 9 cm. If the area of the triangle is 225 cm², then the length of the other leg is
ioda

Given:

One of the legs of a right triangle is 9 cm.

The area of the triangle is 225 cm².

To find:

The length of the other leg.

Solution:

The area of a triangle is

Area=\dfrac{1}{2}\times Base\times Height

The area of a right triangle is

Area=\dfrac{1}{2}\times (leg_1)\times (leg_2)

Let x be the length of other leg.

225=\dfrac{1}{2}\times (9)\times (x)

2\times 225=9x

\dfrac{450}{9}=x

50=x

Therefore, the length of the other leg is 50 cm.

4 0
3 years ago
HELP ME PLS AND THANK YOU
Anna35 [415]
X= - 7/2
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3 0
2 years ago
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Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, projvu u=(-8,8) , v= (
Jobisdone [24]

Answer:

none of the given options is true

Step-by-step explanation:

Given: u=(-8,8) , v= (-1,2)

To find: vectors w_1,w_2 such that u=w_1+w_2

Solution:

A vector is a quantity that has both magnitude and direction.

proj_vu=\frac{u\cdot v}{\left | v \right |^2}(v)\\=\frac{(-8,8)\cdot (-1,2)}{(\sqrt{ (-1)^2+2^2})^2}(-1,2)\\=\frac{8+16}{5}(-1,2)\\=\frac{1}{5}(-24,48)\\=(-4.8,9.6)

Let w_1=(-4.8,9.6)

So,

w_2=u-w_1\\=(-8,8)-(-4.8,9.6)\\=(-8+4.8,8-9.6)\\=(-3.2,-1.6)

So, u = (-4.8,9.6)+(-3.2,-1.6)

So, none of the given options is true

8 0
3 years ago
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