The best thing to do is to find the cost of one sweet, and to do this, divide 42 by 7.
42/7= 6
Therefore, one sweet costs 6p.
To find the cost of 8 sweets, you've got to multiply 6 by 8, and this gives you 54p.
Therefore, 8 sweets cost 54p
Hope this helps :)

6 0

3 years ago

Question 15 of 15Taniah is trying to find the area of the following square whereWY=10. What is the area?

joja [24]

The area of a square given its diagonal (d) is computed as follows:

$A=\frac{1}{2}d^2$

In this case, the diagonal is 10 units long, then the area is:

$\begin{gathered} A=\frac{1}{2}\cdot10^2 \\ A=\frac{1}{2}\cdot100 \\ A=50\text{ square units} \end{gathered}$

8 0

1 year ago

If 3+4+8=15 then 8+3+4=15 right?

Vlada [557]

Yes same thing

love ya
~~~~~~~
Frankie❤

4 0

4 years ago

Finding an Equation of a Tangent Line In Exercise, find an equation of the tangent line to the graph of the function at the give

neonofarm [45]

Answer:

Equation of tangent:

$y = xe^{x}$

At point (1,0):

y = 2.713

Step-by-step explanation:

The equation of tangent line to the function can be calculated by taking the first derivative.

We have,

$y = xe^{x}-e^{x}\\\frac{dy}{dx}=\frac{d}{dx}[ xe^{x} ]-\frac{d}{dx} [e^{x}]\\$

Applying Product Rule:

d/dx [u.v] = (d/dx u) . (v) + (u) . (d/dx v)

Therefore,

$\frac{dy}{dx}=\frac{d}{dx}(x) . e^{x}+x .\frac{d}{dx}(e^{x})- \frac{d}{dx}(e^{x})\\\\\frac{dy}{dx}=(1)(e^{x})+(x)(e^{x})-e^{x}\\ \frac{dy}{dx}=xe^{x}\\\\$

The above equation is the equation of tangent line.

The point given is (1,0):

So,

$\frac{dy}{dx} = (1)e^{1}\\ \frac{dy}{dx} = e\\\frac{dy}{dx} = 2.713$

3 0

3 years ago