Let x be the shorter side, and y be the longer side
There would be 4 fences along the shorter side, and 2 fences along the longer side
4x + 2y = 800
Rewrite in terms of y:
y = 400 − 2x
The area of the rectangular field is
A = x*y
Replace Y with the equation above:
A = x(400 − 2x)
A = − 2x^2 + 400x
The area is a parabola that opens downward, the maximum area would occur at the parabola vertex.
At the vertex
x = −b/2a
= −400/[2(−2)]
= 100
y = 400 −2x
y = 400 -2(100)
y = 400-200
y = 200
The dimension of the rectangular field that maximize the enclosed area is 100 ft x 200 ft.
You need to find the equation of y=Mx+b
Answer is y=-5/3x+5
Brainliest?
Answer:
The answer is (x -5, y -3)
Step-by-step explanation:
Answer:
f mZDEC = (12x – 3), mZBCE = (7x – 26), and mzDAE = 72°, find each angle measure. 12X-3+7X-36 =180. 19x-29 = 180. 19x - 309. X = 11 m<DEC = 12cu1-3.Step-by-step explanation:
