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Andrew [12]
3 years ago
11

11. Use the fact that 19 X 33 = 627 to solve the problems and justify your reasoning

Mathematics
1 answer:
topjm [15]3 years ago
8 0
<h2>19 X 33 = 627,  justified.</h2>

Step-by-step explanation:

We have,

19 × 33 = 627

Use the fact and justify.

L.H.S. = 19 × 33

= (20 - 1) (20 + 13)

Using the identity,

(x - a)(x + b) = x^{2} - (a - b)x - ab

Here, x = 20, a = 1 and b = 13

= 20^{2} - (1 - 13)20 - 1(13)

= 400 - (- 12)20 - 13

= 400 + 240 - 13

= 640 - 13

= 627

= R.H.S., justified.

Thus,  19 X 33 = 627,  justified.

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3 years ago
10+5-7=3y<br><br> -10x+5x+5=-15<br><br> 3x+2x-4x+10<br><br> pre algebra 8th grade math
jasenka [17]

Answer:

1) y=8/3=2 2/3   2) x=4    3) x+10

Step-by-step explanation:

1) 10+5-7=3y

Calculate the sum or difference.

8=3y

Swap the sides of the equation.

3y=8

Divide both sides by 3.

y=8/3=2 2/3

2) -10x+5x+5=-15

Collect like terms.

-5x+5=-15

Move the constant to the right-hand side and change the sign.

-5x=-15-5

Calculate the difference.

-5x=-20

Divide both sides by -5.

x=4

3) 3x+2x-4x+10

Collect like terms.

(3+2-4)x+10

Calculate the sum or difference.

1x+10

When the term has a coefficient of 1, it doesn't have to be written.

x+10

Hope this helps :)

5 0
2 years ago
474 ( ) 548 42. - 8 how do I arrive at this answer.<br>​
dexar [7]

9514 1404 393

Answer:

  (64x^28)/(5y^22)

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

__

First, eliminate the outside exponent on the left factor. Then use the above rules to combine factors with the same base.

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sergiy2304 [10]

Answer:

part A: 30,000 is more

Step-by-step explanation:

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2 years ago
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