19) 5c+c=-6+2
6c=-4
c=-4/6
c=-2/3
20) -20-8=-2e
-28=-2e
28/2=e
14=e
21)p-2w=2l
(p-2w)/2=l
36pi = 4/3 * pi * r^3
27 = r^3
r = 3 in
Add the 28 and 42
then divide by 2
there should be 35 kids in group
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
<em>Pool 1 leaks faster than pool 2.</em>
Step-by-step explanation:
<u>Rates of change</u>
The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.
We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.
To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:
15 minutes = 15/60 = 1/4 hours
20 minutes = 20/60 = 1/3 hours
Now compute both rates of change:
Pool 1:

Pool 2:

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.