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8090 [49]
3 years ago
6

Is the quotient of 3/5 ÷ 6/7 greater than or less than 3/5? Explain

Mathematics
2 answers:
Temka [501]3 years ago
5 0

3/5 divided by 6/7 is 7/10 is greater than 3/5 or 6/10

Vikki [24]3 years ago
3 0

The quotient of two fraction is the multiplication between the first and the inverse of the second:

\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \cdot \dfrac{d}{c}

So, in your case, you have

\dfrac{3}{5} \div \dfrac{6}{7} = \dfrac{3}{5} \cdot \dfrac{7}{6} = \dfrac{7}{10}

So, the question now is: which is larger, 7/10 or 3/5? To answer this question, transform the second fraction so that it will have denominator 10 as well:

\dfrac{3}{5} = \dfrac{3\cdot 2}{5 \cdot 2} = \dfrac{6}{10}

So, now it is clear that

\dfrac{7}{10} > \dfrac{6}{10}

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Solve the following equation: 3x^3+5x^2-4x-4=0
Rama09 [41]

Answer:

1

Step-by-step explanation:

Simplifying

3x + 2(4x + -4) = 3

Reorder the terms:

3x + 2(-4 + 4x) = 3

3x + (-4 * 2 + 4x * 2) = 3

3x + (-8 + 8x) = 3

Reorder the terms:

-8 + 3x + 8x = 3

Combine like terms: 3x + 8x = 11x

-8 + 11x = 3

Solving

-8 + 11x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.

-8 + 8 + 11x = 3 + 8

Combine like terms: -8 + 8 = 0

0 + 11x = 3 + 8

11x = 3 + 8

Combine like terms: 3 + 8 = 11

11x = 11

Divide each side by '11'.

x = 1

Simplifying

x = 1

5 0
3 years ago
A rectangular box with a square base is to be constructed from material that costs $9 per ft2 for the bottom, $5 per ft2 for the
kramer

Answer:

18.73ft^3

Step-by-step explanation:

Let

Side of square base=x

Height of rectangular box=y

Area of square base=Area of top=(side)^2=x^2

Area of one side face=l\times b=xy

Cost of bottom=$9 per square ft

Cost of top=$5 square ft

Cost of sides=$4 per square ft

Total cost=$204

Volume of rectangular box=V=lbh=x^2y

Total cost=9(x^2)+5x^2+4(4xy)=14x^2+16xy

204=14x^2+16xy

204-14x^2=16xy

y=\frac{204-14x^2}{16x}=\frac{102-7x^2}{8x}

Substitute the values of y

V(x)=x^2\times \frac{102-7x^2}{8x}=\frac{1}{8}(102x-7x^3)

Differentiate w.r.t x

V'(x)=\frac{1}{8}(102-21x^2)=0

V'(x)=0

\frac{1}{8}(102-21x^2)=0

102-21x^2=0

102=21x^2

x^2=\frac{102}{21}=4.85

x=\sqrt{4.85}=2.2

It takes positive because side length cannot be negative.

Again differentiate w.r. t x

V''(x)=\frac{1}{8}(-42x)

Substitute the value

V''(2.2)=-\frac{42}{8}(2.2)=-11.55

Hence, the volume of box is maximum at x=2.2 ft

Substitute the value  of x

y=\frac{102-7(2.2)^2}{8(2.2)}=3.87 ft

Greatest volume of box=x^2y=(2.2)^2\times 3.87=18.73 ft^3

5 0
4 years ago
Pleaseee send the answer I’m doing a test pog
Norma-Jean [14]

Answer:

X = 38°

Step-by-step explanation:

There is a therom angles subtended on the remaining part are equal in magnitude

8 0
3 years ago
Which reactant (X) is missing from the equation shown?
Andreas93 [3]

Answer:

three hydrogen atoms

Step-by-step explanation:

H3 + Po4 ----> H3Po4

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8 0
3 years ago
A jar Contains 64 pieces of candy each day two Pieces are eaten After a certain number of days there are 12 pieces of candy left
Elis [28]

The equation I came up with for this one would be 64=12+2x. When you solve this equation start with subtracting twelve, than take 52 (64-12) and divide it by two to figure out how many days it has been (26 days). Hope this helps!

8 0
3 years ago
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