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Stolb23 [73]
3 years ago
12

Find the value of the following expression: (2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whol

e to the power of 4 ⋅ 2^28 (5 points) Write your answer in simplified form. Show all of your steps.
Mathematics
1 answer:
koban [17]3 years ago
4 0

Answer:

\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}

Step-by-step explanation:

\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228

=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}

\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}

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Help will mark and 5 stars and brainliest and THANKS
Leno4ka [110]

Answer:

i would say 105 and if not then its 115

4 0
3 years ago
Read 2 more answers
Help 3 and 4 please!!!!!!!!!!!!
aleksandrvk [35]
Easy peasy

the bit where it says
D={something}
those are the numbers you should input for x to get y values


3.
first solve for y to make life easier
-3x-5y=20
times -1
3x+5y=-20
minus 3x both sides
5y=-3x-20
divide both sides by 5
y=-3/5x-4
sub value of the domain
x=-10
y=-3/5(-10)-4
y=6-4
y=2
a point is (-10,2)

x=-5
y=-3/5(-5)-4
y=3-4
y=-1
(-5,-1) is another

x=0
y=-3/5(0)-4
y=-4
(0,-4) is another

x=5
y=-3/5(5)-4
y=-3-4
y=-7
(5,-7)

points are (-10,2), (-5,-1), (0,-4), (5,-7)



4.
input
x=-2
y=(-2)^2-3
y=4-3
y=1
(-2,1)

x=-1
y=(-1)^2-3
y=1-3
y=-2
(-1,-2)

x=0
y=(0)^2-3
y=-3
(0,-3)

x=1
y=(1)^2-3
y=1-3
y=-3
(1,-3)

x=2
y=(2)^2-3
y=4-3
y=1
(2,1)

the points are (-2,1), (-1,-2), (0,-3), (1,-2), (-2,1)

see graph below

5 0
3 years ago
Shoutout to lester bc i know he's gonna answer this ;) !
MrMuchimi

Answer:

A (-3,9)

Step-by-step explanation:

ok easy they they us

R(2,1) and R'(-4,8)

subtract 6 from y and add 7 to y

ok lets solve for S'

S(3,2) now subtract 6 and add 7

(3,2)+(-6,7)

(-3,9)

5 0
3 years ago
5 numbers with 8 in the ones place
STatiana [176]

Answer:

the answer to this question is 58

Step-by-step explanation:

mark me as brainliest

4 0
2 years ago
3. In the diagram shown, midpoints F and G are located with segments CG and DF intersecting at H. If CH =10 then which of the fo
Nana76 [90]

The midpoint given illustrates that the length of the segment CG will be C. 15.

<h3>What is a midpoint?</h3>

It should be noted that in geometry, the midpoint simply means the middle point of a line segment.

In this case, from the diagram given, midpoints F and G are located with segments CG and DF intersecting at H and CH =10.

Therefore, the length of CG will be:

= 10 + (1/2 × 10)

= 10 + 5

= 15

In conclusion, the length of CG is 15.

Learn more about midpoint on:

brainly.com/question/16828532

4 0
2 years ago
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