Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
the answer is B...i swear its B
Answer:
A = 1/24
Step-by-step explanation:
Area is the length times the width
A = l*w
The length is 1/6 and width is 1/4
A = 1/6*1/4
A = 1/24
Younger than = less than
Less than symbol = <
People cannot have a negative age, so a must be positive
B. <span>a < 18 and a must be a positive number</span>
D=4n-2, d+2=4n-2+2, d+2=4n
(d+2)/4=(4n)/4, 1/4d+1/2=n
n=1/4n+1/2
size 3=
n=1/4*3/1=3/4, 3/4+1/2=5/4=1 1/4
size 3=1 1/4
size 6=
n=1/4*6/1=6/4, 6/4+1/2=8/4=2
size 6=2
size 10=
n=1/4*10/1=10/4, 10/4+1/2=12/4=3
size 10=3
